3 years ago

Solve each equation with the quadratic formula. 4n^2+7n-1=-4

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

7 0

The answer i got was
n=-3/4,n=-1

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Which point satisfies the inquality 2×+y > 10 a. (2,3) b.(3,4) c. (3,2) d. (4,3)

Anna11 [10]

D. (4,3) that's the answer

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4 years ago

Find an equation in point-slope form for the line having the slope m= -5 and containing the point (7,2).

Juli2301 [7.4K]

Answer:

y - 2 = - 5(x - 7)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

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Here m = - 5 and (a, b) = (7, 2) , thus

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Answer:

Step-by-step explanation:

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Ans

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4 years ago

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If you would like to know how many minutes were spent on language arts, you can calculate this using the following steps:

60% of 40 minutes = 60% * 40 = 60/100 * 40 = 24 minutes

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Find limit as x approaches 2 from the left of the quotient of the absolute value of the quantity x minus 2, and the quantity x m

Molodets [167]

Answer:

$\lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1$ .

Step-by-step explanation:

We want to find $\lim_{x \to 2^-} \frac{|x-2|}{x-2}$ .

By definition:

$|x-2|=\left \{ {{x-2,\:if\:x\:>\:2} \atop {-(x-2),\:if\:x\:$

Since we want to find the Left Hand Limit, we use f(x)=-(x-2)

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} \frac{-(x-2)}{x-2}$ .

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=\lim_{x \to 2} (-1)$ .

The limit of a constant is the constant.

$\implies \lim_{x \to 2^-} \frac{|x-2|}{x-2}=-1$ .

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3 years ago