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skad [1K]
3 years ago
9

Solve the following function for y when x=5 round to the nearest tenth

Mathematics
1 answer:
Wittaler [7]3 years ago
7 0

In the given question , we have a function given , which is

y= 13(0.5^x)

And we need to find the value of y when x=5.

So we substitute 5 for x and solve for y, that is

y=13(0.5^5) = 0.40625

And on rounding to the nearest tenths, we will get

y=0.4

So when x=5, y=0.4

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Svetach [21]

Answer:

B

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3 0
3 years ago
Please answer my questions is really easy but idk
GrogVix [38]

Given:

m \angle A B D=96^{\circ}

m \angle 2 =m \angle 1+ 26^{\circ}

To find:

m \angle 1

Solution:

m \angle DBC+ m \angle CBA = m \angle ABD

m \angle 1+ m \angle 2 = m \angle ABD

Substitute m \angle 2 =m \angle 1+ 26^{\circ}.

m \angle 1+ m \angle 1 + 26^\circ = 96^\circ

2m \angle 1+ 26^\circ = 96^\circ

Subtract 26° from both sides.

2m \angle 1+ 26^\circ -26^\circ = 96^\circ -26^\circ

2m \angle 1 = 70^\circ

Divide by 2 on both sides, we get

m \angle 1=35^{\circ}

Therefore, m∠1 = 35°.

8 0
4 years ago
Read 2 more answers
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