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3 years ago

14

Select the correct answer from the drop-down menu. The lengths of three line segments are 4 centimeters, 5 centimeters, and 9 ce

ntimeters. Using this information, triangles can be constructed.
a. 0
b. 1
c.2
d.many

1 answer:

MrMuchimi3 years ago

4 0

I believe the answer is (B) 1 TIME

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The submarine is 217 feet below sea level. Identify the integer

Sever21 [200]

Answer:

okay

Step-by-step explanation:

6 0

3 years ago

Ed has $5.06.<br> He finds $1.03.<br> About how much $ does he have now?

OverLord2011 [107]

Answer:

Ed now has $6.09

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3 years ago

Read 2 more answers

Early in 2022, Pina Company switched to a just-in-time inventory system. Its sales revenue, cost of goods sold, and inventory am

balu736 [363]

The Inventory Turnover for 2021 is 5.9 times and for 2022 is 10 times.

<h3>Inventory turnover</h3>

2021

Inventory Turnover = Cost of Goods sold / Average Inventory

Cost of Goods sold = $1,165,250/[($170,000+$225,000)/2]

Cost of Goods sold = $1,165,250/($395,000/2)

Cost of Goods sold = $1,165,250/197,500

Cost of Goods sold = 5.9 times

2022

Inventory Turnover = Cost of Goods sold / Average Inventory

Cost of Goods sold = $1,525,000/[($225,000+$80,000)/2]

Cost of Goods sold = $1,525,000/($305,000/2)

Cost of Goods sold = $1,525,000/152,500

Cost of Goods sold = 10 times

Therefore the Inventory Turnover for 2021 is 5.9 times and for 2022 is 10 times.

Learn more about Inventory Turnover here:brainly.com/question/12942515

#SPJ1

The complete question is:

Pina Colada Corp. switched to a just-in-time inventory system. Its sales and Inventory amounts for 2021 and 2022 are shown below.

2021 2022

Sales revenue $3,360,000 $3,900,000

Cost of goods sold 1,165,250 1,525,000

Beginning inventory 170,000 225,000

Ending inventory 225,000 80,000

Determine the inventory turnover for 2021 and 2022.

4 0

2 years ago

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

3 years ago

A rectangle that has an area of 357 square inches is 17 inches wide. Using the formula for area (A=lw), how long is the rectangl

Lynna [10]

----------------------------------------------------------------------------------------
Formula
----------------------------------------------------------------------------------------
Area of rectangle = Length x Width

----------------------------------------------------------------------------------------
Find Length
----------------------------------------------------------------------------------------
357 = Length x 17

----------------------------------------------------------------------------------------
Divide by 17 through
----------------------------------------------------------------------------------------
Length = 357 ÷ 7
Length = 51 inches

----------------------------------------------------------------------------------------
Answer: The length of the rectangle is 51 inches
----------------------------------------------------------------------------------------

7 0

4 years ago