Answer:
x = -9
y = -8
Step-by-step explanation:
here's the solution :-
=》y = 2x + 10
=》y = x + 1
plunging the value of y from equation 1 into equation 2
=》2x + 10 = x + 1
=》2x - x = 1 - 10
=》x = -9
value of x = -9
now, plugging the value of x in equation 2, we get :-
=》y = x + 1
=》y = -9 + 1
=》y = -8
Answer:
30:9
Step-by-step explanation:
Answer:
3 is the slope
Step-by-step explanation:
Answer:
Step-by-step explanation:
as the temp t increases the number of cricket chirps also increases.
5. Answer: see explanation
<u>Step-by-step explanation:</u>
If the roots are m and 3m, then x = m and x = 3m
⇒ x - m = 0 and x - 3m = 0
⇒ (x - m)(x - 3m) = 0
⇒ x² - 4mx + 3m² = 0
Since x² + px + q = 0 then p = -4m and q = 3m²
3p² = 3(-4m)² 16q = 16(3m²)
= 3(16m²) = 48m²
= 48m²
3p² = 48m² = 16q ⇒ 3p² = 16q
**********************************************************************************************
6. Answer: 8 or 18
<u>Step-by-step explanation:</u>
The Area of the entire rectangle (A = L × w) is 12 × 10 = 120
The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.
There are two non-shaded triangles.
- Bigger non-shaded Δ: L = 12-x, w = 10 ⇒

- Smaller non-shaded Δ: L = x, w = x ⇒

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

Area of ΔBEF:
