I did the problem and I got negative 4 over 9
The frequency table, stem and leaf plot, and histogram are attached.
The histogram looks similar to the stem and leaf plot, except turned on its side. It is different from the frequency table in shape, but the numbers in the table are the same as the size of the bars.
The height of the bars in the histogram is the same as the number of leaves in the stem and leaf plot, and it is also the same as the numbers in the frequency table. Using larger intervals will result in larger bars on the histogram and larger numbers in the frequency table; smaller intervals will result in smaller bars and smaller numbers in the table.
Answer:
A. day 12
Step-by-step explanation:
because that is when both lines meet
brainliest please :)
You don't even have to look up the definition of 'standard deviation'. You only
have to remember that 'smaller standard deviation' means 'less spread-out'.
First, let's find the mean (average). It's not supposed to change:
1/7th of (65 + 71 + 77 + 80 + 82 + 90 + 96) = 561/7 = <u>80 and 1/7</u> .
Now, just pick 7 scores that total 561 and are all bunched up.
The easiest way would be 80, 80, 80, 80, 80, 80, 81 .
But that's so easy that it feels like cheating.
Let's say <u>77, 78, 79, 80, 81, 82, and 84</u> .
Answer:
bottom left
Step-by-step explanation:
parallel lines will never intersect