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2 years ago

Solve for x and y when 1x -250y = 86

Mathematics

2 answers:

RSB [31]2 years ago

7 0

Answer:

x=250y+86

Step-by-step explanation:

hope this helps

Elodia [21]2 years ago

4 0

Answer:

x=250y+86

Step-by-step explanation:

add 250 to both sides

x−250y+250y=86+250y

x=250y+86

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Point K is graphed on a number line at 3. Point L is 11 units away from point K on the number line.

notsponge [240]

3+/-11
add 11 to 3
11+3=14
minus 11 from 3
3-11=-8

the coordinate could be 14 or -8

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3 years ago

On a map, 1 inch equals 15 miles. Two cities are 2 inches apart on the map. What is the actual distance between the cities?

BabaBlast [244]

Since the scale is 15 miles per inch all you need to do is multiply.
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In a town of 40,000 people, it is expected 41.9% will watch the Súper bowl. How many people in the town will watch the Súper bow

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Step-by-step explanation:

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3 years ago

cara played a card game using a deck of 52 cards after she dealt the same number of cards to 4 players she had 24 cards left ov

Dmitriy789 [7]

Answer:

Step-by-step explanation:

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3 years ago

Sum of cubes: (a b)(a2 – ab b2) = a3 b3 Difference of cubes: (a – b)(a2 ab b2) = a3 – b3 Which products result in a sum or diffe

valentina_108 [34]

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

$(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3$

(a)

$(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\$

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

$(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

$(x+1)(x-1)=x^{2}-1^{2}\\$

we can say that this is neither sum nor difference of cube as it's difference of squares.

(d)

$(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)$

by comparison with formula this is equal to

$x^{3}+4^{3}\\$

Hence this is sum of cubes

(e)

$(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)$

by comparison with formula we can say that this is neither sum nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that $(x+4)\left(x^{2}-4 x+16\right)$ is sum of cubes

To know more about cubes visit: brainly.com/question/107100

8 0

2 years ago