Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
As given in the question,
P(x) be the given polynomial
Dividing P(x) by divisor (x-6) we get,
Quotient = Q(x)
Remainder = 5
Relation between polynomial, divisor, quotient and remainder is given by :
P(x) = Q(x)(x-6) + 5 __(1)
Given Q(-6) = 3
Put x =-6 we get,
P(-6) = Q(-6)(-6-6) +5
⇒ P(-6) = 3(-12) +5
⇒ P(-6) =-36 +5
⇒ P(-6) = -31
Now x =6 in (1),
P(6) = Q(6)(6-6) +5
⇒ P(6) = Q(6)(0) +5
⇒ P(6) = 5
Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
The complete question is:
Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).
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37
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Well you said the answer in your question
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2
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The degree of the polynomial is the highest exponent of an expression. When more than one variable is present, its is the sum of exponents on one term in the expression.
The polynomial has terms xy, 3x^2, -7 and x. The term with the highest exponent sum is xy or 3x^2. Both have degree 2. The degree of the polynomial is 2.
The answer is 333. put the 3 and the 2 in the correct spots. then multiply 8 and 2 which is 16 then 7 and 3 which is 21. then add which is 37. you would have to multiply 37 and 9 and you would get 333.
Answer:
?
Step-by-step explanation: