Reflecting over the x-axis in words and formula

Mathematics

1 answer:

Ksivusya [100]3 years ago

4 0

Answer:

Formula: (x, -y), when reflecting over the x-axis you keep the x-value the same, but change the sign of the y-value. For example: You have the original coordinates (3, 5), and if you reflect it over the x-axis it’ll be (3, -5).

You might be interested in

Mary and tom were buying a present for their mother on mothers day. mary spent $12 and tom spent $28 if they wanted to share the

Alina [70]

16 dollars is how much mary owes tom

4 0

3 years ago

Read 2 more answers

∫∫(x+y)dxdy ,d là miền giới hạn bởi x²+y²=1

igor_vitrenko [27]

It looks like you want to compute the double integral

$\displaystyle \iint_D (x+y) \,\mathrm dx\,\mathrm dy$

over the region D with the unit circle x ² + y ² = 1 as its boundary.

Convert to polar coordinates, in which D is given by the set

D = {(r, θ) : 0 ≤ r ≤ 1 and 0 ≤ θ ≤ 2π}

and

x = r cos(θ)

y = r sin(θ)

dx dy = r dr dθ

Then the integral is

$\displaystyle \iint_D (x+y)\,\mathrm dx\,\mathrm dy = \iint_D r^2(\cos(\theta)+\sin(\theta))\,\mathrm dr\,\mathrm d\theta \\\\ = \int_0^{2\pi} \int_0^1 r^2(\cos(\theta)+\sin(\theta))\,\mathrm dr\,\mathrm d\theta \\\\ = \underbrace{\left( \int_0^{2\pi}(\cos(\theta)+\sin(\theta))\,\mathrm d\theta \right)}_{\int = 0} \left( \int_0^1 r^2\,\mathrm dr \right) = \boxed{0}$