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3 years ago

Reflecting over the x-axis in words and formula

Mathematics

1 answer:

Ksivusya [100]3 years ago

4 0

Answer:

Formula: (x, -y), when reflecting over the x-axis you keep the x-value the same, but change the sign of the y-value. For example: You have the original coordinates (3, 5), and if you reflect it over the x-axis it’ll be (3, -5).

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3 years ago

Rewrite 9cos 4x in terms of cos x.

rosijanka [135]

$\bf \qquad \textit{Quad identities}\\\\
sin(4\theta )=
\begin{cases}
8sin(\theta )cos^3(\theta )-4sin(\theta )cos(\theta )\\
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\\\\\\
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---------------------------------------------------------------------------

as far as the previous one on the 2tan(3x)

$\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\qquad tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}\\\\
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\\\\\\
2\left[ \cfrac{\frac{2tan(x)}{1-tan^2(x)}+tan(x)}{1-\frac{2tan(x)}{1-tan^2(x)}tan(x)}\right]\implies 2\left[ \cfrac{\frac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}}{\frac{1-tan(x)-2tan^3(x)}{1-tan^2(x)}} \right]
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$\bf 2\left[ \cfrac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}\cdot \cfrac{1-tan^2(x)}{1-tan(x)-2tan^3(x)} \right]
\\\\\\
2\left[ \cfrac{3tan(x)-tan^3(x)}{1-tan^2(x)-2tan^3(x)} \right]\implies \cfrac{6tan(x)-2tan^3(x)}{1-tan^2(x)-2tan^3(x)}$

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3 years ago

You are playing a card game with friends. at one point. you double your score. in the next hand you lose 75 points. you end up w

Gnoma [55]

Answer:

i) x points; ii) 2x - 75 = -25; iii) x = 25

Step-by-step explanation:

i) Starting points

Let's say you had x points before doubling your score.

(ii) The equation

After doubling score: 2x points

After losing 75 points: (2x - 75) points

At end of game: -25 points

The equation is

2x - 75 = -25

iii) Solution to equation

2x - 75 = -25 Add 75 to each side

2x = 50 Divide each side by 2

x = 25

3 0

3 years ago