Question

Identify the area of the rhombus.

Answer 1

Answer:

$A=240\ m^{2}$

Step-by-step explanation:

we know that

A rhombus is a parallelogram with four congruent sides, the diagonals are perpendicular bisectors of each other

The area of a rhombus is equal to

$A=\frac{1}{2}(D1*D2)$

where

D1 and D2 are the diagonals

In this problem we have

$D1=16\ m$

Applying the Pythagoras Theorem find D2

$17^{2} =(D2/2)^{2}+(16/2)^{2}$

$(D2/2)^{2}=17^{2}-(16/2)^{2}$

$(D2/2)^{2}=225$

$(D2/2)=15$

$D2=30\ m$

Find the area of the rhombus

$A=\frac{1}{2}(16*30)=240\ m^{2}$