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anygoal [31]
2 years ago
10

PLEASEEEEEE HELPPPppppp

Mathematics
1 answer:
STALIN [3.7K]2 years ago
4 0

Answer:

A

Step-by-step explanation:

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Find the widest range of scores that you can get on a final exam in order to receive a grade of B for the class. Using interval
Drupady [299]

Answer:

Correct choice is B

Step-by-step explanation:

Let x% be your final test score, then the average of all test scores is

\dfrac{96+77+74+x}{4}.

Since you must have an average between 80% and 89%, then

80\le \dfrac{96+77+74+x}{4}\le 89,\\ \\320\le 247+x\le 356,\\ \\73\le x\le 109.

X is measured in percent, then the greatest value of x can be 100%. You get that

73\%\le x\le 100%.

4 0
3 years ago
Read 2 more answers
When Anna was born 16 years ago, her small town of Lewisville had a population of 15,000. The population has increased 11% each
ZanzabumX [31]
<span>16 years ago = - 16
Present population -16 = </span><span>15,000 (population)
</span>
11% increase = every year =0.11

present year = <span>15,000 x 0.11^16 
                     = 15,000 x 4.594
approx = 68,925</span>
7 0
3 years ago
Read 2 more answers
Write 4 3/7 as a decimal.
Citrus2011 [14]
Hi!

There are two ways to do this. 

1. Start with the first part of the decimal, (4.) then divide 3/7 to get the second part. 

3/7 = 0.43

4.43

2. Convert the mixed number 4 3/7 to a fraction. 

4 x 7 = 28
28 + 3 = 31

31/7

Now convert that into a decimal.

31/7 = 4.43

The answer is 4.43

Hope this helps! :)
3 0
3 years ago
Read 2 more answers
HELPP!!
SSSSS [86.1K]

Answer:

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

7 0
3 years ago
Reviews of call center representatives over the last three years showed that 10% of all call center reps were rated as outstandi
spayn [35]
I believe the answer is A goodluck
8 0
2 years ago
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