I would first add 5 and 2 together, then multiply that by 3. Finally you would subtract the 1. After solving for what is inside the parentheses you would multiply it by 2 for your final answer.
2•(3(5+2)-1)
2•(3(7)-1)
2•(21-1)
2•(20)
40
Answer:a) 54/55
b) 100/110
c) 99/110
Step-by-step explanation:
a)Probability of ordering 4= 9/12×3/11×2/10×1/9 = 54/11880
Probability of 4 good units= 4 × 54/11880
= 216/11880
1/55
1-(1/55) = 54/55
b)Probability of 2 good units= 2 × 54/(11880)
= 108/11880
= 1/110
1- (1/110)= 100/110
c) Probability of exactly 2 units not good= 1 -(100/110) =99/110
Answer:
he is an ordinary man because that is what the speaker is talking about
For the first 60 positive integers, a = 1, n = 60, l = 60.
Sn = n/2(a + l)
s = 60/2(1 + 60) = 30(61)
For the next 60 positive integer, a = 61, n = 60, l = 120
Sum = 60/2(61 + 120) = 30(61 + 120) = 30(61) + 30(120) = s + 3600
Sum of first 120 positive integers = s + s + 3600 = 2s + 3600
