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Lorico [155]
2 years ago
9

Two consecutive whole numbers total 17. Find the larger.

Mathematics
1 answer:
kolbaska11 [484]2 years ago
6 0

Answer:

9

Step-by-step explanation:

Consecutive means in a row

x = 1st number

x+1 = 2nd number

x+x+1 = 17

Combine like terms

2x+1 = 17

Subtract 1 from each side

2x+1-1=17-1

2x = 16

Divide each side by 2

2x/2 =16/2

x=8

x+1 = 9

The larger number is 9

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RDY AND NDA are what?
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Answer:

Vertical and Supplementary

Step-by-step explanation:

Vertical:

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8 0
3 years ago
Find all solutions to
BARSIC [14]

Answer:

x= 0 , \frac{1}{14} , \frac{-1}{12}

Step-by-step explanation:

Given, equation is \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x}. →→→ (1)

Now, by cubing the equation on both sides, we get

( \sqrt[3]{15x-1} + \sqrt[3]{13x+1} )³ = (4\sqrt[3]{x})³

⇒ (15x-1) + (13x+1) + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{15x-1} + \sqrt[3]{13x+1}) = 64 x.

⇒ 28x + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (4\sqrt[3]{x}) = 64x.        

(since from (1),  \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x})

⇒ 12× \sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{x})= 36x.

⇒ 3x = \sqrt[3]{(15x-1)(13+1)(x)}.

Now, once again cubing on both sides, we get

(3x)³ = (\sqrt[3]{(15x-1)(13+1)(x)})³.

⇒ 27x³ = (15x-1)(13x+1)(x).

⇒ 27x³ = 195x³ + 2x² - x

⇒ 168x³ + 2x² - x = 0

⇒ x(168x² + 2x -1) = 0

⇒ by, solving the equation we get ,

x = 0 ; x = \frac{1}{14} ; x = \frac{-1}{12}

therefore, solution is x= 0 , \frac{1}{14} , \frac{-1}{12}

7 0
3 years ago
Which of the following is a factor<br> of the expression 5x^2- 13x-6?
tatiyna

Answer:

(5x+2) (x-3)

Step-by-step explanation:

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2 years ago
What is the answer of 37&lt;7-10w?
FrozenT [24]

Answer:

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Step-by-step explanation:

Interval notation form is:

(-∞,-3)

8 0
3 years ago
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