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irga5000 [103]
4 years ago
5

Solve the system by the method of your choice x=3y-6,2x-6y=-12

Mathematics
1 answer:
igor_vitrenko [27]4 years ago
8 0

The "system" of equations can't be solved for (x, y), because there's no "system" of equations given.  There's really only one equation.

Either of these two equations can be massaged to look exactly like the other one.  And if you graph both equations, you find that they're both the same line on the graph.

ANY point on the line is a solution to both equations ... and we all know how many different points there are on a line.

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Two times a number added to another number is 25. Three times the first number minus the second number is 20. What are both numb
lawyer [7]

Answer:

the two number are 7 and 9

Step-by-step explanation:

2*x+y=25

3x-y = 20

add the two equations

2*x+y=25

3x-y = 20

---------------

5x = 45

divide by 5

5x/5 = 45/5

x = 9

lets find y

2x+y = 25

substitute x

2*9 +y =25

18+y =25

subtract 18 from both side

y = 25-18

y =7

7 0
3 years ago
Drag a statement or reason to each box to complete the proof.
astra-53 [7]

Answer:

The answers of the proof are the following:

2. Division Property of Equality

3. x+ 1 = -4

4. Subraction Property of Equality

5. x = -5

5 0
3 years ago
Find the centroid for an area defined by the equations y = x² + 3 and y = - (x – 2)² + 7
sergeinik [125]
First we need to find where the 2 graphs intercept.

x^2 + 3 = - (x^2 - 4x + 4) + 7
x^2 + 3 = -x^2 + 4x + 3
2x^2 - 4x = 0 
2x(x - 2)

x = 0 , 2. are x coordinates  of the 2 intercepts.

6 0
3 years ago
Jessica weighed her dog at the end of each month for three months. At the end of the first month, her dog gained 12.48 pounds. A
uranmaximum [27]

Answer:59.39pounds

Step-by-step explanation:

Because you add 26.34+20.57+12.48 and then you will he 59.39points

6 0
3 years ago
ABC is a tangent to the circle below. O is the centre of the circle. Work out the size of angle 0. Give reasoning to justify you
Delvig [45]

Answer:

Θ = 46°

Step-by-step explanation:

the angle between a tangent and a radius at the point of contact is 90° , so

∠ ABO = 90°

since OB = OD ( radii of circle ) then Δ BOD is isosceles and

∠ OBD = ∠ ODB = 22°

the exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ AOB is an exterior angle of the triangle , then

∠ AOB = 22° + 22° = 44°

the sum of the 3 angles in Δ AOB = 180° , then

Θ + 44° + 90° = 180°

Θ + 134° = 180° ( subtract 134° from both sides )

Θ = 46°

6 0
2 years ago
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