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KiRa [710]
3 years ago
10

What is the product of StartFraction 4 Over 5 EndFraction times StartFraction 3 Over 7 EndFraction?

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
5 0

Answer:

\frac{12}{35}

yes

charle [14.2K]3 years ago
5 0

Answer:

B. 85/12

Step-by-step explanation:

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So say selling a backpack thats used-like new and the original price is $54.00 how much should I set the price at??
Nat2105 [25]

it most be eleven hundred

6 0
3 years ago
Read 2 more answers
Giá trị x thoả mãn x(x − 3) + x − 3 =0 là
svet-max [94.6K]

Here we will use the trial and error method.

  • We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
5 0
3 years ago
How to get to the answer
Ilia_Sergeevich [38]

Answer:

\large\boxed{C)\ F(x)=2^x+1}

Step-by-step explanation:

C)\ F(x)=2^x+1\\\\\text{Put the values of x from the table to the equation of a function:}\\\\F(3)=2^3+1=8+1=9\qquad\ CORREC\\F(4)=2^4+1=16+1=17\qquad CORRECT\\F(6)=2^6+1=64+1=65\qquad CORRECT\\F(7)=2^7+1=128+1=129\qquad CORRECT\\F(8)=2^8+1=256+1=257\qquad CORRECT

7 0
3 years ago
what is c to the negative 3 power and d to the 5 power over f to the 3 power and g to the negative 7 power
julia-pushkina [17]

Answer:

C^-3+d^5/f^3+g^-7

Step-by-step explanation:

The answer is as seen above

8 0
2 years ago
Please help me quickly
s2008m [1.1K]
A function is defined as a set of points for every x-value, there is only one y-value.
So, you can't have two y-values for every x-value.

Thus, (B) would be a relation, because x = 7 has two y-values, and as such, doesn't satisfy the condition of a function.
3 0
3 years ago
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