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3 years ago

What is the product of StartFraction 4 Over 5 EndFraction times StartFraction 3 Over 7 EndFraction?

Mathematics

2 answers:

Juli2301 [7.4K]3 years ago

5 0

Answer:

$\frac{12}{35}$

yes

charle [14.2K]3 years ago

5 0

Answer:

B. 85/12

Step-by-step explanation:

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The reciprocal of a positIve natoinal number is?

sleet_krkn [62]

Answer:

If the rational number is ab then, te reciprocal is ba

Step-by-step explanation:

Suppose that rational number is ab

Then, the reciprocal of that number is ba

3 0

3 years ago

Please help with my algebra 1 homework thank you

MrRissso [65]

1) Answer:

$\frac{4m^{10} }{9n^{18} }$

2) Answer:

$8m ^{5}$

The answer for first equation is, option B.

and the Answer for Second equation is option D.

6 0

3 years ago

(h(1) = 14 h(n) 28 hin - 1) h(2) =

Serhud [2]

Answer:

Y=ax2

Step-by-ste:

Y=ax28(n)

5 0

3 years ago

Find the value of each variable in the parallelogram.

kenny6666 [7]

Answer:

n = 12 , m = 5

Step-by-step explanation:

since it is said it is a parallelogram so opposite sides are equal

n = 12 (being opposite sides of parallelogram)

m + 1 = 6 (being opposite sides of parallelogram)

m = 6 - 1

m = 5

Hope it will help :)

7 0

3 years ago

A survey of 90 men found that an average amount spent on St. Patrick's day of $55 with a standard deviation of $18. A similar su

dem82 [27]

Answer:

The value of the test statistic is 4.70.

Step-by-step explanation:

The hypothesis for this test can be defined as follows:

H₀: Men do not spend more than women on St. Patrick's day, i.e. μ₁ = μ₂.

Hₐ: Men spend more than women on St. Patrick's day, i.e. μ₁ > μ₂.

The population standard deviations are not known.

So a t-distribution will be used to perform the test.

The test statistic for the test of difference between mean is:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }$

Given:

$\bar x_{1}=55\\s_{1}=18\\n_{1}=90\\\bar x_{1}=44\\s_{1}=16\\n_{1}=86$

Compute the value of the test statistic as follows:

$t=\frac{\bar x_{1}-\bar x_{2}}{\sqrt{\frac{s^{2}_{1}}{n_{1}}+\frac{s^{2}_{2}}{n_{2}}} }=\frac{55-44}{\sqrt{\frac{15^{2}}{90}+\frac{16^{2}}{86} }}=4.70$

Thus, the value of the test statistic is 4.70.

7 0

3 years ago