Answer:
$1.35
Step-by-step explanation:
x: quarter=$0.25
y: dime=$0.10
z: nickel=$0.05
so total amount of changes
= (0.25*x)+(0.10*y)+(0.05*z)
x=3, y=5, z=2
substituting into the eqn
total = (0.25*3)+(0.10*5)+(0.05*2)
= 0.75 + 0.5 + 0.1
= $1.35
Answer:
![$\[x^2 + 22x + 121\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20121%5C%5D%24)
Step-by-step explanation:
Given
![$\[x^2 + 22x + \underline{~~~~}.\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20%5Cunderline%7B~~~~%7D.%5C%5D%24)
Required
Fill in the gap
Represent the blank with k
![$\[x^2 + 22x + k\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20k%5C%5D%24)
Solving for k...
To do this, we start by getting the coefficient of x
Coefficient of x = 22
<em />
Divide the coefficient by 2


Take the square of this result, to give k


Substitute 121 for k
![$\[x^2 + 22x + 121\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20121%5C%5D%24)
The expression can be factorized as follows;




<em>Hence, the quadratic expression is </em>
<em></em>
Answer:
Your anwser is (-3 -4)
Step-by-step explanation:
Hope this helps you! 'v'
Answer:
ewfyeet
Step-by-step explanation:
Answer:
The number of times it would take more than 27 minutes to manufacture a pair of running shoes is 2.275 times or approximately 2 times per every 100 shoes
Step-by-step explanation:
The average time it takes to manufacture a pair of shoes = 21 minutes;
The standard deviation = 3 minutes
To find how often it takes more than 27 minutes to manufacture a pair of running shoes, we have;
Standard score, given as follows;

Where;
x = The raw score = 27 minutes
μ = The average score = 21 minutes
σ = The standard deviation = 3 minutes
From which we have;

Therefore, it is borderline unusual with a p value of P(z>2) = 1 - 0.97725 = 0.02275
Therefore, the number of times out of 100 that it would take more than 27 minutes to manufacture a pair of running shoes = 100 × 0.02275 = 2.275 times which is approximately 2 times in every 100 shoes.