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3 years ago

B) Here are the first four terms of a quadratic sequence.

Mathematics

1 answer:

Nookie1986 [14]3 years ago

5 0

Find answer is the given attachment

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Pls help me this is a 66 point question I need real answers

larisa86 [58]

Does G equal 2.3?. because this is a very diffacult problem, but the answer may very well be 2.3.

3 0

3 years ago

Read 2 more answers

The purchasing director of a bank has just received a shipment of 100 printers. She has been told that the shipment includes 5 d

zaharov [31]

Since there is a 95% chance that you get two printers right, then you simply square the decimal equivalent which is .95 (Hence, you do .95^2). You will get .9025 (or 90.25%).

For letter b, you simply subtract .9025 from 1.
ans = 1-.9025
ans = .0975 (or 9.75%)

So the answer to B) would be there is a 9.75% chance the probability of a shipment can be rejected.

8 0

3 years ago

Which two points are on the graph of y = -x + 3?

ch4aika [34]

The points (0, 3) and (4, -1) are on the graph of y = -x + 3.

I have a site that I use a lot that is perfect for problems like these. It's called Desmos.com. It's basically a free online graphing calculator that is super helpful for most problems relating to graphs.

3 0

3 years ago

What is the median of 77, 84, 85, 88, and 99?

telo118 [61]

Answer:

86.6

Step-by-step explanation:

77+84+85+88+99=433

433/5=86.6

7 0

3 years ago

Read 2 more answers

Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mp

romanna [79]

Answer:

C. 210 miles

Step-by-step explanation:

We have been given that two cars leave Phoenix and travel along roads 90 degrees apart. Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mph.

We will use distance formula and Pythagoras theorem to solve our given problem.

$\text{Distance}=\text{Speed}\times \text{Time}$

$\text{Distance covered by Car 1 in 3.5 hours}=\frac{42\text{ Miles}}{\text{Hour}}\times \text{3.5 hour}$

$\text{Distance covered by Car 1 in 3.5 hours}=147\text{ Miles}$ .

Since car 1 leaves 30 minutes before car 2, so car 2 will travel for only 3 hours when car 1 will travel for 3.5 hours.

$\text{Distance covered by Car 2 in 3 hours}=\frac{50\text{ Miles}}{\text{Hour}}\times \text{3 hour}$

$\text{Distance covered by Car 2 in 3 hours}=150\text{ Miles}$

Since both car travel along roads 90 degree apart, therefore, the distance between both cars after Car 1 has traveled 3.5 hours would be hypotenuse with legs 147 and 150.

$\text{Distance between both cars}=\sqrt{147^2+150^2}$

$\text{Distance between both cars}=\sqrt{21609+22500}$

$\text{Distance between both cars}=\sqrt{44109}$

$\text{Distance between both cars}=210.021427\approx 210$

Therefore, the both cars will be 210 miles apart and option C is the correct choice.

3 0

3 years ago