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Goryan [66]
3 years ago
11

PLEASE HELP!!!!!!! A family has two cars. The first car has a fuel efficiency of 35 miles per gallon of gas and the second has a

fuel efficiency of 20 miles per gallon of gas. During one particular week, the two cars went a combined total of 1450 miles, for a total gas consumption of 50 gallons. How many gallons were consumed by each of the two cars that week?
Mathematics
1 answer:
Marianna [84]3 years ago
4 0

Answer:

The answer to your question is car 1 = 30 gal and car 1 = 20 gal

Step-by-step explanation:

car 1 = a

car 2 = b

Efficiency of car 1 = 35 mi/gal

Efficiency for car 2 = 20 mi/gal

Total distance = 1450

Total gas consumption = 50 gal

Equations

                          35a + 20b = 1450            ------- (I)

                             a   +     b =  50               ------- (II)

Solve by elimination

Multiply equation II by -35

                          35a  + 20b  = 1450

                         -35a  - 35b   = -1750

Simplify

                            0    - 15b    =  -300

Solve for b

                                        b =  -300/-15

Result

                                        b = 20

Substitute b in equation II to find a

                               a +  20  = 50

Solve for a

                               a  = 50 -20

Result

                               a  = 30

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Answer:

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Step-by-step explanation:

5x^2+10x^1−6x^2x+3

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Answer:

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3 0
3 years ago
A concert sold general admission tickets for $47.50 and lower-level seating for $97.50. The 995 tickets sold took in $68,762.50.
BabaBlast [244]

Answer: 565 general admission and 430 lower-level seating tickets sold (Answer (D))

Steps:

Let x be the number of general admission tickets, and y be the number of lower level tickets.

Set up the two equations:

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solve for x, y:

x = 995 - y

plug into the first equation:

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solve for y:

y = 430

then x = 565

x = 565 and y = 430


8 0
3 years ago
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Step-by-step explanation:

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2 years ago
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Step-by-step explanation:

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2 years ago
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