Answer:
22.86% probability that the persons IQ is between 110 and 130
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

If one person is randomly selected what is the probability that the persons IQ is between 110 and 130
This is the pvalue of Z when X = 130 subtracted by the pvalue of Z when X = 110.
X = 130



has a pvalue of 0.9772
X = 110



has a pvalue of 0.7486
0.9772 - 0.7486 = 0.2286
22.86% probability that the persons IQ is between 110 and 130
Answer:
$2000
Step-by-step explanation:
For each pound, the charge is $40. There are 50 such charges. The point of multiplication is to simplify the process of repeated addition.
... 50 × $40 = $2000
Since the two lines are parallel, the angle labeled 130 is congruent to the angle labeled x+ 136 so you can set them equal to each other
130 = x + 136
subtract 136 from both sides
x = -6
Answer:
128 ft/s; it represents the average speed of the object between 2 seconds and 6 seconds
Step-by-step explanation:
The average rate of change is another way to say slope.
slope = (y2-y1)/(x2-x1)
= (576-64)/(6-2)
= (512/4)
=128 ft/s
This represents the change in ft per second, or the average speed the object is going during the time period.