A rectangular plot of farmland will be bounded on one side by a river and on the other three sides by a single-strand electric f
ence. With 400 m. of wire at your disposal what is the largest area that you can enclose, and what are its dimensions? Use the convention that length is longer than the width.
<span>2x+y=400
A=xy area of farmland
y=400-2x
A=400x-2x^2
A'(x)= 400 -4x derivative of area with respect to x
0=400-4x find out where f ' equals 0
4x=400
x=100
A'(x)= 400 -4x
A''(x)= -4 check 2nd derivative. if negative then relative max at x=100
2x+y=400
y=200
dimensions 100x200
hope it helped</span>
First you do $60 divided by 4 which equals $15 Then you take 1% of 15 which is 0.15 and multiply thirty percent by that and subtract thirty percent from 100% and get 70% which is 10.5
