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attashe74 [19]
3 years ago
6

A rectangular plot of farmland will be bounded on one side by a river and on the other three sides by a single-strand electric f

ence. With 400 m. of wire at your disposal what is the largest area that you can enclose, and what are its dimensions? Use the convention that length is longer than the width.
Mathematics
1 answer:
Tpy6a [65]3 years ago
7 0
<span>2x+y=400 A=xy area of farmland y=400-2x A=400x-2x^2 A'(x)= 400 -4x derivative of area with respect to x 0=400-4x find out where f ' equals 0 4x=400 x=100 A'(x)= 400 -4x A''(x)= -4 check 2nd derivative. if negative then relative max at x=100 2x+y=400 y=200 dimensions 100x200 hope it helped</span>
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If \frac{6}{10} is multiplied with a fraction less than 1, out of the given options \frac{1}{2} would be the answer.

Explanation:

  • First, we need to determine what a fraction lesser than 1 is. If the numerator is lesser than the denominator, the fraction will be lesser than 1 whereas if the denominator is higher than the numerator is would equal more than 1.
  • If \frac{6}{10} is multiplied with 1, we get the value \frac{6}{10}. Since the fraction must be lesser than 1, \frac{6}{10} cannot be an answer. So option 1 cannot be the answer.
  • The value of \frac{6}{10} is 0.6. If it is multiplied with any value lesser than 1, the resulting value cannot be higher than the value of 0.6. The value of the fraction \frac{3}{2} is 1.5 and the value of 5 are both greater than 0.6. So the third and fourth options cannot be the answer. So \frac{1}{2} is the answer.

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Answer:

See below...

Step-by-step explanation:

For a function whose formula is in this pattern:

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Amplitude: 4

Period: \frac{2\pi}{2}=\pi

Phase Shift: \frac{3\pi}{4}

There is no vertical shift, so the midline is the x-axis whose equation is y = 0.

Also, because there is no vertical shift, the maximum is 4 and the minimum is -4.

The graph is attached.

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= 1/32, or 0.03125.

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Answer:

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