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Yanka [14]
3 years ago
13

The slope-intercept form of a linear equation is y = mx + b, where x and y are coordinates of an ordered pair, m is the slope of

the line, and b is where the line crosses the y-axis.
Which is an equivalent equation solved for the slope, m?

a. m = yx + b
b. m =
c. m = – b
d. m = y –
Mathematics
2 answers:
exis [7]3 years ago
6 0

y=mx+b

subtract b over so that

y-b=mx

then divide by x so the answer is

m=(y-b)/x

Savatey [412]3 years ago
5 0

Divide both sides by x + b to get m by itself. The equation will look like this: m = \frac{y}{x+b}

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liubo4ka [24]
(Multiply all by 3 )
7x+x=3+5x
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I need help on 24 please
dusya [7]
Where's the table. you need it to answer the questions.
4 0
3 years ago
Approximately how many times as great is the volume of a grapefruit with a diameter 16 cm as the volume of a lime with a diamete
SIZIF [17.4K]

Answer: The volume of the grapefruit is approximately 8 times as great as the volume of the lime.

Step-by-step explanation:

You need to use the formula for calculate the volume of a sphere. This is:

V=\frac{4}{3}\pi  r^3

Where "r" is the radius.

<u>Volume of the grapefruit</u>

You know that its diameter is 16 centimeters.

Since the radius is half the diameter, you get that its volume is:

V_g=\frac{4}{3}\pi  (\frac{16\ cm}{2}) ^3\\\\V_g= 2,144.66\ cm^3

<u> Volume of the lime</u>

According to the information given in the exercise, the diameter of the lime is 8 centimeters.

As it was explained above, the radius is half the diameter. Knowing that, you get that volume of the lime is the shown below:

V_l=\frac{4}{3}\pi  (\frac{8\ cm}{2}) ^3\\\\V_l= 268.08\ cm^3

In order to find approximately how many times as great is the volume of theat grapefruit as the volume of that lime, you need to divide the volumes calculated above. Then:

\frac{2,144.66\ cm^3}{268.08\ cm^3}\approx8\ times

8 0
3 years ago
I will give brainlist if you answer all these questions please! I promise I will :))
lawyer [7]
2. C
3. C
4. C

(all answers are c)
4 0
3 years ago
What are the excluded values of x for <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%2B1%7D%7Bx%5E2-1%7D%20" id="TexFormula1"
NISA [10]
Denominator:

x^2-1=(x+1)(x-1)=\big(x-(-1)\big)(x-1)

so excluded values are x =  -1 and x = 1.

Answer D.
8 0
3 years ago
Read 2 more answers
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