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zheka24 [161]
3 years ago
8

HEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
5 0
The answer is 5/4 ....so go for that !!! C
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A polygon with side lengths of 6, 9, and 15 forms a triangle. <br> True <br> False
Butoxors [25]

Try this: Combine 6 and 9, obtaining 15.

Compare this sum, 15, to the length of the 3rd side: 15.


If placed end to end, the 2 sides with lengths 6 and 9 form a new line of length 15. We'd end up with this new line superimposed on the 3rd side (with length 15).


Think: Do 2 straight lines of length 15, superimposed on one another, form a triangle?


3 0
4 years ago
Read 2 more answers
-1/2(10x + 2) - 7 = -x - 4
xxTIMURxx [149]
The answer would be -1. ☺️
7 0
4 years ago
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Solve the proportional equation 2/3 = x/15
dimulka [17.4K]
  2            x
 -----  =  ------
  3           15

cross multiply
(3)(x) = (15)(2)
3x = 30
x = 30/3
x = 10

so 2/3 = 10/15.......notice how these are equivalent fractions....that is because proportions are nothing but equivalent fractions
5 0
3 years ago
Suppose that two teams are playing a series of games, each of which is independently won by team A with probability p and by tea
Lady_Fox [76]

Answer:

4 games played = 1/56

5 games played = 5/56

6 games played = 15/56

7 games played = 35/56

Step-by-step explanation:

The probability of each time winning is 0.5

So there are a couple of ways the series could go.

  1. Team A could win all first 4 matches. We can depict this as A-A-A-A
  2. Team A could win 4, while having lost 1.  Lets depict this a A-B-A-A-A
  3. Team A could win 4, while having lost 2. A-B-B-A-A-A
  4. Team A could win 4, while having lost 3. A-B-B-B-A-A-A

These 4 possibilities could be repeated with B winning as well. It should be noted that these are the only ways for the series to end. We find the number of permutations of each possibility above to find their probability.

I advise you to study 'how to permute identical objects' for this.

These permutations are stated below:

1. 4!/4! = 1

2. \frac{5!}{4! * 1!} = 5

3 \frac{6!}{4! * 2!} = 15

4 \frac{7!}{4! * 3!} = 35

These are they ways A or B could win. The total is 1+5+15+35 = 56. The answer given thus reflects the possibilities.

4 0
4 years ago
Evan has 5 tennis balls, 2 footballs and 2 packages of golf balls with 4 balls in each. What is the ratio of tennis balls to his
Sedbober [7]

Answer:

5/13 or 38.41%

Step-by-step explanation:

7 0
3 years ago
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