Answer:
1,333 frogs
Step-by-step explanation:
okay so we know that mass remains conserved no matter where you are.
same here ^^
if the total mass of brass is 200 kg
the total mass of the new frogs formed from it when put together will be the same :)
and if there were n such frogs formed
we have,
total mass = n × mass of each frog
200 = n × 3/ 20
n = 4000/ 3
so it becomes something like 1,333.33
that is nearly 1,333 frogs can be made out of 200 kg of brass each weighing 3/ 20kg (the last ones a bit less to make upto 200kg)
To evaluate the combination we proceed as follows:
21C3
Given nCk we shall have:
n!/[(n-k)!k!]
thus plugging the values in the expression we get:
21!/[(21-3)!3!]
=21!/(18!×3!)
=1330
Answer: 1330
Hey guys im gonna be really nice, ima give you the answers for connexus <span>Geometry Semester B: 1) D 2) B 3) A 4) D 5) B 6) C 7) D 8) A 9) A 10) NO 11) OBTUSE 12) C 13) A 14) D 15) B 16) A 17) LAST GRAPH 18) D 19) A 20) B 21) B 22) B 23) C 24) A 25) B 26) A 27) A 28) B 29) B 30) B 31) A 32) A 33) B 34) B 35) B 36) D 37) A 38) A 39) A 40) B 41) D 42) A 43) B 44) A 45) B 46) D 47) C 48) A 49) D 50) D
These r 100% correct i promise if ur in connexus you will get all correct! hope this helps you guys out :3</span>
<span>[2×(10+5)]-5
[2*15]-5
30-5
25</span>
Answer:
1. D 2. A 3. Distribute the four in 4(x+1)
Step-by-step explanation:
1. It says that Jamie is saying that they are "not equivalent".
2. You have to use the distributive property to distribute the 4 to x and to the 1.
3. After distributing, compare the two expressions and now see if they are equivalent or not.
