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3 years ago

7

Terri gets most of her exercise by walking briskly. Last year she walked an average of 4.2 miles per day with a standard deviati

on of 1.2 miles per day. April swims for exercise last year she swam for a mean of 40 minutes per day with a standard deviation of 8 minutes per day. For the new year, both girls have resolved to exercise more. In January Terri walked an average of 6 miles per day while April swam for an average of one hour per day. Which girl is off to a better start relation to their results from the previous year?

1 answer:

Alinara [238K]3 years ago

3 0

Terri walked in her own 93rd percentile, while April swam in her own 99th percentile. April is off to a slightly better start.

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Read 2 more answers

A population of mice is increasing exponentially. On Monday there were 120 most. One month later there were 132 most. Ready func

djyliett [7]

Answer:

$y=120 * 1.1^x$ --- function

The monthly rate is 10%

Step-by-step explanation:

Given

Let

$x \to months$

$y \to mice$

So, we have:

$(x_1,y_1) = (0,120)$ --- Monday

$(x_2,y_2) = (1,132)$ --- One month later

Required

The function

The function is represented as:

$y=ab^x$

In $(x_1,y_1) = (0,120)$ , we have:

$120 = a * b^0$

$120 = a * 1$

$120 = a$

$a=120$

In $(x_2,y_2) = (1,132)$ , we have:

$132 = a * b^1$

$132 = a * b$

Substitute: $a=120$

$132 = 120 * b$

Solve for b

$b = \frac{132}{120}$

$b = 1.1$

So, the function is:

$y=ab^x$

$y=120 * 1.1^x$

To calculate the monthly rate (r), we have:

$y =a(1 + r)^x$

Compare to: $y =ab^x$

$1 + r = b$

Make r the subject

$r = b-1$

Substitute $b = 1.1$

$r = 1.1-1$

$r = 0.1$

Express as percentage

$r = 0.1*100\%$

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