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Ugo [173]
3 years ago
12

Tommy is making a greeting card on his computer. He can choose 1 of 4 backgrounds, 1 of 7 photos, and 1 of 6 text colors. How ma

ny ways can Tommy make a greeting card?
A.17
B.34
C.66
D.168
Mathematics
2 answers:
Pani-rosa [81]3 years ago
8 0

Answer: D.168

Step-by-step explanation:

Given: Tommy is making a greeting card on his computer. He can choose 1 of 4 backgrounds, 1 of 7 photos, and 1 of 6 text colors.

It means there is no repetition .

Now, the number of ways Tommy can make a greeting card is given by :-

4\times7\times6=168

Hence, the number of ways Tommy can make a greeting card is 168.

Dahasolnce [82]3 years ago
5 0
Answer is D. 168

4 x 7= 28
28 x 6= 168
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A tank initially contains 50 gallons of brine, with 30 pounds of salt in solution. Water runs into the tank at 6 gallons per min
balandron [24]

Answer:

1.857 minutes

Step-by-step explanation:

From the given information:

Consider the amount of salt present in the tank as x(t) at a given time (t); &

The volume of the solution = V(t)

At t = 0 i.e. (at initial conditions)  x(0) = 30; and V(0) = 50

However, the overall increase taken place for 1 gallon per minute is:

V(t) = 50 + t

The amount of salt x(t) at any given point for time (t) is;

\dfrac{x(t)}{V(t)}= \dfrac{x(t)}{50+t}

After 5 gallons of solution exit per minute; the concentration of the salt solution changes at:

\dfrac{dx(t)}{dt}= -\dfrac{5x(t)}{50+t}

Taking the integral of what we have above, we get:

In x(t) = - 5 In(t + 50) + In (C)

In x(t) = In (t+ 50)⁻⁵ + In (C)

In x(t) = In C ( t + 50)⁻⁵

x(t) = C(t + 50)⁻⁵      (General solution)

To estimate the required solution; we apply the initial conditions x(0) = 30;

Thus;

x(0) = C(50)⁻⁵ = 30

⇒ C = 30 × 50⁵

Hence; x(t) =  30 × 50⁵ × (t + 50)⁻⁵

The above expression can be re-written as:

x(t) = 25 \implies 30 \times \bigg ( \dfrac{50}{t+50} \bigg ) ^5= 25

i.e.

\bigg ( \dfrac{50}{t+50} \bigg ) ^5= \dfrac{25}{30}

\dfrac{50}{t+50}= \bigg ( \dfrac{25}{30}\bigg) ^{\dfrac{1}{5}}

\dfrac{50}{t+50}= 0.964192504

{50}= 0.964192504(t+50)

50 = 0.964192504t + 48.2096252

50 - 48.2096252 = 0.964192504t

1.7903748 =  0.964192504t

t = 1.7903748 / 0.964192504

t ≅ 1.857 minutes

We can thereby conclude that the estimated time it will require until there are 25 pounds of salt in the tank is 1.857 minutes.

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3 years ago
The water level of a lake depleted by 1.2 inches during a 13 week long dry spell. What is
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»»————-Question:————-««

The water level of a lake depleted by 1.2 inches during a 13 week long dry spell.

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1.2÷13=0.0153

*°:⋆ₓₒ Hope this helps! (ෆ˙ᵕ˙ෆ)♡ If my answer is wrong, please correct me! Thank you!ₓₒ⋆:°*

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6 0
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