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PolarNik [594]
3 years ago
7

Can someone plz help me?

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
7 0
Sorry man i can't help you
but i think it's y=25,x=100
n200080 [17]3 years ago
4 0
The equation of the line best fit is y=35, x= 20
no practice, student expcted to type 20 wpm
every minute spent practicing typing speed increased by 1/2  word per minute
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hey ppl i forgot to add the drop down options on my last question so i made a new one with the options
Kipish [7]

Use the commutative Property of Addition to  add the last two terms first.

9 + (-17) + (-9) = -17

Hope this helps!! Good luck. :)

3 0
2 years ago
The ratio of the length of a rectangular field to its width is 4:3. If the length of the field is 100 meters, what is the perime
irina [24]

Answer:

350

Step-by-step explanation:

divide 100/4= 25

25*3=75 so width = 75 meters

perimeter= 2(l+w)

perimeter= 2(100+75)

perimeter= 2(175)

perimeter= 350

6 0
3 years ago
Suppose theta is an angle in the standard position whose terminal side is in quadrant 4 and cot theta = -6/7. find the exact val
zimovet [89]

First off, let's notice that the angle is in the IV Quadrant, where sine is negative and the cosine is positive, likewise the opposite and adjacent angles respectively.

Also let's bear in mind that the hypotenuse is never negative, since it's simply just a radius unit.

\bf cot(\theta )=\cfrac{\stackrel{adjacent}{6}}{\stackrel{opposite}{-7}}\qquad \impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{6^2+(-7)^2}\implies c=\sqrt{36+49}\implies c=\sqrt{85} \\\\[-0.35em] ~\dotfill

\bf tan(\theta)=\cfrac{\stackrel{opposite}{-7}}{\stackrel{adjacent}{6}} ~\hfill csc(\theta)=\cfrac{\stackrel{hypotenuse}{\sqrt{85}}}{\stackrel{opposite}{-7}} ~\hfill sec(\theta)=\cfrac{\stackrel{hypotenuse}{\sqrt{85}}}{\stackrel{adjacent}{6}} \\\\\\ sin(\theta)=\cfrac{\stackrel{opposite}{-7}}{\stackrel{hypotenuse}{\sqrt{85}}}\implies \stackrel{\textit{and rationalizing the denominator}}{sin(\theta)=\cfrac{-7}{\sqrt{85}}\cdot \cfrac{\sqrt{85}}{\sqrt{85}}\implies sin(\theta)=-\cfrac{7\sqrt{85}}{85}}

\bf cos(\theta)=\cfrac{\stackrel{adjacent}{6}}{\stackrel{hypotenuse}{\sqrt{85}}}\implies \stackrel{\textit{and rationalizing the denominator}}{cos(\theta)=\cfrac{6}{\sqrt{85}}\cdot \cfrac{\sqrt{85}}{\sqrt{85}}\implies cos(\theta)=\cfrac{6\sqrt{85}}{85}}

6 0
2 years ago
Write a inequality for the graph below
max2010maxim [7]

Answer:

X ≥ -6

Step-by-step explanation:

since the arrow is pointing towards the right side i.e tending towards x

7 0
2 years ago
4. Between which two whole<br> numbers does V150 lie?
KonstantinChe [14]

Answer:

12 & 13

Step-by-step explanation:

trust me

3 0
3 years ago
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