Question

Algebra question please help

Answer 1

First, determine the domain:  x ≥ 0  (because you can't square root a negative)

Next, square both sides of the equation and solve for "x".

(√x)² < (5)²

+/- x < 25

+x < 25        -x < 25

 x< 25           x > -25  ⇒ Remember the domain is x ≥ 0

x < 25   and  x ≥ 0 ⇒ 0 ≤ x

Answer: 0 ≤ x < 25    interval notation [0, 25)

 

Answer 2

(square root of x)^2 < (5)^2

x<25