7. Select each problem that has a quotient of 0.4* 16 = 40 24 = 6 60 = 16 3.6

The estimated product of 20.7 and 9.18, after rounding both factors to the nearest whole number,

lesya692 [45]

Answer:

20.7 --> 21

9.18 --> 9

21x9 is 189, thus the estimated product is 189.

Let me know if this helps!

7 0

2 years ago

HELP ASAP!!! (Question and answers pictured)

BARSIC [14]

9514 1404 393

Answer:

(d) reflection about the x-axis, up 6 units

Step-by-step explanation:

The parent function y=1/x is multiplied by -1, which reflects it over the x-axis. Then 6 is added, which shifts it up 6 units.

The transformations are ...

reflection about the x-axis, up 6 units

6 0

2 years ago

Refer to your math writing journal file named "Lines and Angles." What real-world examples did you describe for the three ways i

Sav [38]

Answer:

Railway lines are example of parallel lines
The floor and the walls of a room are example of perpendicular lines
Two roads crossing at a signal can be termed as example of intersecting lines

Step-by-step explanation:

The lines can be related in following three ways

Lines can be parallel
Lines can be perpendicular
Lines can be intersecting at an angle other than 90.

Now three real life examples of above three scenarios are described below:

Railway lines are example of parallel lines
The floor and the walls of a room are example of perpendicular lines
Two roads crossing at a signal can be termed as example of intersecting lines

6 0

3 years ago

Write an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the line described by y=1/2

Marat540 [252]

Given:

The point, (4, -3)

The line,

$y=\frac{1}{2}x+5$

To find an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the given line:

The slope of the line is,

$m=\frac{1}{2}$

Since the given line is parallel to the new line, so the slope will be same for the both.

Using the point-slope formula,

$y-y_1=m(x-x_1)$

Substitute the point and slope we get,

$\begin{gathered} y-(-3)=\frac{1}{2}(x-4) \\ y+3=\frac{1}{2}x-2 \\ y=\frac{1}{2}x-2-3 \\ y=\frac{1}{2}x-5 \end{gathered}$

Hence, the equation in slope-intercept form for the line is,

$y=\frac{1}{2}x-5$

8 0

1 year ago

Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0

3 years ago

Read 2 more answers

7. Select each problem that has a quotient of 0.4* 16 = 40 24 = 6 60 = 16 3.6 - 9