Bright cherry red color is produced upon the addition of methyl red indicator to a culture of a Gram negative bacilli in MR-VP broth if the organism used the mixed acid pathway of fermentation.
What is MR-VP test?
- As part of the IMViC testing, Methyl Red (MR) and Voges-Proskauer (VP) broth is utilized as the medium in which both the Methyl Red and Voges-Prosakuer tests can be conducted.
- It is a straightforward broth made up of dextrose or glucose, buffers, and peptone.
- In the Methyl Red test, an infected tube of MR-VP broth is mixed with the pH indicator methyl red.
- The acids will overwhelm the buffers in the medium and create an acidic environment if the organism employs the mixed acid fermentation pathway and creates stable acidic end products.
- If acidic end products are present when methyl red is introduced, the methyl red will remain red.
Learn more about the MR-VP test with the help of the given link:
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The deer eat grass. Its droppings, which eventually decompose into the ground, provide minerals and vitamins to the plant roots. This food is vital for it so the plant remains alive and can produce oxygen which is essential for the deer and grass is also a food source for him too.
The correct answer is: B) flesh of another animal
The shape of teeth is tightly connected with the food that animal eats.Examples:
• Herbivores (plant eaters) have flat teeth specialized for the grass chewing.
• Carnivores (flesh eaters) have long and sharp teeth for meat cutting.
• Omnivores (eat meat and plants) such as humans have various types of teeth with different functions.
There are four main types of teeth: incisors (at the front, sharp for cutting), canines ( to grip and tear food), premolars (flat surface for food crushing), molars (the biggest with flat biting surface, to chew).
Answer:
its number 1
Explanation:
because the fly is stuck in amber
and the snail shell is in mold and is filled up
and number 2 is not cast
The genealogy tree which is missing from the question is in the attachment.
Answer: 1) P1 = 
; 2) P2 = ; 3)P3 = 
Explanation: 1) According to the genealogy tree, the individual III-3 has a P1 = 1/2, because each of the parents are heterozygous for the condition, since one of the ofspring is affected.
2) For individual III-4, one of the parents is heterozygous for the condition, so the probability of being a carrier is P2 = 1/2.
3) Now, for individual IV-1 be affected, the parents has to be carrier. So, this probability, depends on the probability of each parent being heterozygous and that the individual will be carrying the condition, which means:
P3 = 1/2 · 1/2 · 1/4 = 1/16.
The probability of having the condition is 1/16 or 6.25%.
