I need help one this one
1 answer:
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Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.
Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.
Therefore, the angle BKQ is equal to 180-50-45=85°.
Of course angle BKP=180-85=95°.
Hope this helps :)
Answer:
Step-by-step explanation:
d = c/pi
so d = 62.8/pi
d = 62.8/pi or appr 19.99in
r = d/2
so r = 62.8/2pi or 31.4/pi appr 19.99/2
so
then
so
a = approximately 313.84
answer is rowan