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blagie [28]
3 years ago
8

SOMEONE FIND THE ANSWER, ILL GIVE BRAINLIEST.

Mathematics
1 answer:
My name is Ann [436]3 years ago
6 0
<h2>AREA:</h2>

SQUARE IN THE MIDDLE

This is the easiest part: a square with side length s has area s^2, so the area of the square in the middle is

A_s = 12^2=144

TRIANGLE ON THE LEFT

The base of this triangle is one side of the square, so it is 12 inches long. The height is given, and it is 8 inches long. The area of a triangle is half the product of width and height, and so we have

A_t = \dfrac{12\cdot 8}{2}=48

SEMICIRCLE ON THE RIGHT

The diameter of the semicircle is one side of the square, so it is 12 inches long. The radius is half the diameter, so it's 6 inches long. The area of a circle is \pi r^2, so the area of a semicircle will be half this quantity:

A_c = \dfrac{\pi r^2}{2}\approx \dfrac{3.14\cdot 36}{2}=56.52

The total area is the sum of these areas:

A=A_s+A_t+A_c=144+48+56.52=248.52

<h2>PERIMETER:</h2>

As for the perimeter, we have:

  • The two sides of the triangle, which are 10 inches each.
  • The top and bottom sides of the square
  • Half the circumference of the circle

Since the circumference of a circle is 2\pi r, the semicircumference will be \pi r

So, the perimeter is

10+10+12+12+6\pi \approx 44+6\cdot 3.14=62.84

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