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galben [10]
3 years ago
12

Evaluate the function. f(x) = 3x2 + 16 Find f(-1)

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
4 0

Answer:

f(-1)=19

Step-by-step explanation:

<u>Evaluating Functions</u>

Given a function y=f(x), evaluate the function for x=a means substituting the variable for the given value.

We have the function:

f(x)=3x^2+16

Find f(-1):

f(-1)=3(-1)^2+16

f(-1)=3(1)+16

f(-1)=3+16

\boxed{f(-1)=19}

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U - 5.3 = 3.99 gxmdksgsjdkd
Rina8888 [55]

Answer:

Assuming you want to find u, u = 9.29

Step-by-step explanation:

u - 5.3 = 3.99

Add 5.3 to both sides.

u = 3.99 + 5.3

u = 9.29

5 0
3 years ago
A study9 compared personality characteristics between adult children of alcoholics and a control group matched on age and gender
34kurt

Answer:

df.= 28

P - value = 0.0124 < 0.05

There is a difference between the mean of  the well-being measure for the children of alcoholics, and a mean of the control group.

Step-by-step explanation:

As the given test is dependent or paired test the degrees of freedom is n-1 = 20-1 = 28

The reported t = 2.67

The P value for ∝= 0.05 at  calculated t= 2.67 and 28 d.f is 0.0124 which is less than 0.05 .

The null hypothesis is rejected.

The null hypothesis is that there is no difference between the means of the two samples.

H0: u1 = u2

The alternate hypotheis is accepted that there is  difference between the means of the two samples.

Ha: u1≠ u2

There is a difference between the mean of  the well-being measure for the children of alcoholics, and a mean of the control group.

4 0
3 years ago
Can someone help me?
Marysya12 [62]
Yeah whatchu need homie
5 0
3 years ago
The black graph is the graph of y =f(x). Choose the equation for the red graph. A. y - 1 = f() B. y + 1 = f() C. = f(x - 1) D. f
Rom4ik [11]

Answer: C

Step-by-step explanation:

The red graph is the result of reflecting the graph of y=f(x) across the x-axis and then translating 1 unit to the right.

5 0
2 years ago
The number of students in the tutoring center was recorded for 47 randomly selected times. The data is summarized in the frequen
ddd [48]

Using the information given, it is found that the class width for this frequency distribution table is of 1.

In this problem, these following classes are given:

0 – 1 14

2 – 3 1

4 – 5 8

6 – 7 12

8 – 9 12

The classes not given, which are 1 - 2, 3 - 4 and 5 - 6, have values of 0.

The <u>difference between the bounds of the classes is of 1</u>, thus, the class width is of 1.

A similar problem is given at brainly.com/question/24701109

5 0
3 years ago
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