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3 years ago

H²+10h=-21 solve quadratic trinomials

Mathematics

1 answer:

sladkih [1.3K]3 years ago

5 0

H²+10h+21 = 0
h²+3h+7h+21 = 0
h(h+3)+7(h+3) = 0
(h+3)(h+7) = 0

h+3=0
h = -3

h+7=0
h=-7

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Answer:

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2 years ago

Trigonometric identities assignment 4

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Answer:

<em>Answer: choice D.</em>

Step-by-step explanation:

<u>Trigonometric Functions</u>

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2 years ago

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3 years ago

Read 2 more answers

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lara [203]

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3 years ago

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ziro4ka [17]

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<h3>Briefing:</h3>

Distribute 2j to (j+3).

Rewrite the summation as the sum of two individual summations.

Evaluate each summation using properties or formulas from the lesson.

The lower index is 1, so any properties can be used.

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<h3>Calculation according to the statement:</h3>

$\sum_{j=1}^{200} 2 j(j+3)$