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Alborosie
3 years ago
12

1 pound is closest in weight to which one of the following Metric units of weight?

Mathematics
1 answer:
timama [110]3 years ago
8 0

Answer:

<h2>4.5 N</h2>

Step-by-step explanation:

To convert 1 pounds to its meteric unit in weight, we need to first convert it to kilogram. Using the conversion 1pound = 0.453592 kg

Since Weight of a substance = mass of the substance * acceleration due to gravity

W = mg

Given mass = 0.453592kg and g = 9.8m/s²

Weight = 4.4452016 Newtons

1 pounds is therefore closest to 4.5 units metric of weight

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El cociente de dos números es 20​
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Answer: y cuál es la pregunta?????

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3 0
2 years ago
Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin9t,sin6t,9t⟩,r(0)=⟨4,6,3⟩
klemol [59]

\mathbf r'(t)=\langle\sin9t,\sin6t,9t\rangle


\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt


\mathbf r(t)=\left\langle\displaystyle\int\sin9t\,\mathrm dt,\int\sin6t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle


\displaystyle\int\sin9t\,\mathrm dt=\frac19\cos9t+C_1

\displaystyle\int\sin6t\,\mathrm dt=\frac16\cos6t+C_2

\displaystyle\int9t\,\mathrm dt=\frac92t^2+C_3


With the initial condition \mathbf r(0)=\langle4,6,3\rangle, we find


\dfrac19\cos0+C_1=4\implies C_1=\dfrac{35}9

\dfrac16\cos0+C_2=6\implies C_2=\dfrac{35}6

\dfrac92\cdot0^2+C_3=3\implies C_3=3


So the particular solution to the IVP is


\mathbf r(t)=\left\langle\dfrac19\cos9t+\dfrac{35}9,\dfrac16\cos6t+\dfrac{35}6,\dfrac92t^2+3\right\rangle

4 0
3 years ago
What is greater 2/5 or 35/100
Alenkasestr [34]
2/5 is greater because it would equal 40/100 which is greater than 35/100

8 0
3 years ago
Read 2 more answers
A number divided by three less two is at most two
Marina CMI [18]

x ≤ 12

Solution:

Let us take the number be x.

A number : x

A number divided by three : $\frac{x}{3}

A number divided by three less two : $\frac{x}{3}-2

A number divided by three less two is at most two : $\frac{x}{3}-2\leq 2

Now, simplify the inequality,

$\Rightarrow\frac{x}{3}-2\leq 2

Add 2 on both sides of the inequality,

$\Rightarrow\frac{x}{3}-2+2\leq 2+2

$\Rightarrow\frac{x}{3}\leq 4

Multiply by 3 on both sides of the equation,

$\Rightarrow\frac{x}{3}\times3\leq 4\times3

$\Rightarrow x\leq 12

Hence x ≤ 12.

5 0
4 years ago
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