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Liula [17]
3 years ago
10

For conducting a​ two-tailed hypothesis test with a certain data​ set, using the smaller of n1minus−1 and n2minus−1 for the degr

ees of freedom results in dfequals=​11, and the corresponding critical values are tequals=plus or minus±2.201. Using the formula for the exact degrees of freedom results in dfequals=​19.063, and the corresponding critical values are tequals=plus or minus±2.093. How is using the critical values of tequals=plus or minus±2.201 more​ "conservative" than using the critical values of plus or minus±​2.093? Choose the correct answer below. A. Using the critical values of tequals=plus or minus±2.201 requires fewer calculations than using the critical values of plus or minus±2.093. B. Using the critical values of tequals=plus or minus±2.201 results in rounding the test statistic to more decimal places than using the critical values of plus or minus±2.093. C. Using the critical values of tequals=plus or minus±2.201 is more likely to lead to rejection of the null hypothesis than using the critical values of plus or minus±2.093. D. Using the critical values of tequals=plus or minus±2.201 is less likely to lead to rejection of the null hypothesis than using the critical values of plus or minus±2.093.

Mathematics
1 answer:
Schach [20]3 years ago
8 0

Answer:

D. Using the critical values of t=±2.201 is less likely to lead to rejection of the null hypothesis than using the critical values of ±2.093.

Step-by-step explanation:

solution is solved below,

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OK so we need to find the function v(t) which will tell us where the particle is at any given time.

We know that the derivative of distance is speed and the derivative of speed is acceleration.

In this case we need to work backwords and find the integrals.


a(t) = 13 sin(t) + 4 cos(t)

s(t)= integral of above = 13(-cos(t)) + 4(sin(t)) + C

v(t)= integral of above = -13sin(t) -4cos(t) +Ct + D


Now I believe you have incorrect initial conditions

s(0) = 0, s(2π) = 10

As cos and sin functions have the same value at 0 and 2Pi the above cannot be true.

My guess is that one is s(0) and the other is v(2Pi) or the other way round.

These initial conditions will determine the value of the two constants: C and D.


Hope this helps.

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8TH GRADE GEOMETRY:100 POINTS+BRAINLIEST: Please answer the question and explain how you did it. Also, please tell me what a "ra
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Answer:

Option B       1 : 3

Step-by-step explanation:

<u></u>

<u>Volume formulas & definitions:</u>

To solve this problem, we must remember the formulas for volume of each shape:

V_{cylinder}=\pi r^2h\\V_{cone}=\frac{1}{3} \pi r^2 h  where r represents the radius of the circular part of the shape, and h represents the height of the shape (the plural of height is "heights", and the plural of radius is "radii")

So, when the question states that the shapes "have congruent heights and radii" it means that the height of both objects is the same, and the radius of both objects is the same.

<u>Ratios</u>

To find the ratio of the volume of the cone to the volume of the cylinder, we must setup the ratio.  Ratios can be setup as a fraction where the first quantity is the numerator (top of fraction), and the second quantity is the denominator (bottom of the fraction):

\dfrac{V_{cone}}{V_{cylinder}}=\dfrac{\frac{1}{3} \pi r^2 h} {\pi r^2 h}

Since the pi, the "r", and the "h" are the same in both the numerator and denominator (and since there is only multiplication & division in the fraction) these common factors can cancel, and reduce the fraction to the following:

\dfrac{V_{cone}}{V_{cylinder}}=\dfrac{\frac{1}{3}} {1}

Any number divided by 1 doesn't change, so one-third divided by 1 is still one-third.

\dfrac{V_{cone}}{V_{cylinder}}=\frac{1}{3}

<u>Other representations of ratios</u>

Lastly, we must remember that a ratio an also be written with a colon symbol, where the numerator is written first, and the denominator is written second.

So, the ratio of the volume of the cone to the volume of the cylinder is:

1 : 3

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