Answer:
![\left[\begin{array}{cccc}1&3&4&5\&3&1&5&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%263%264%265%5C%263%261%265%266%5Cend%7Barray%7D%5Cright%5D)
The only ones are on the "diagonal", where i = j. Else the position is simply the sum.
Answer:
One Solution
Step-by-step explanation:
That's My Answer :)
3-i/2
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Answer:
Step-by-step explanation:
Given:
Radius of circular mirror, r = 6x
Length of metal frame, l = 18x
Area of square, As = l^2
Area of square = 18x × 18x
= 324 x^2.
Area of circular mirror, Ac = pi × r^2
= π × (6x)^2
= 36π x^2.
The expression for the area of the frame is subtracting the mirror from the metal frame = As - Ac
= 324x^2 - 36πx^2
= 36x2 (9 - π).