Answer:
- TU = UV = VW = WT = 8
- WX = UX = 5
- XV = XT = √39
Step-by-step explanation:
At first we should know the following about the rhombus
1) All sides are congruent
2) The diagonals are perpendicular and bisects each other.
Given UV = 8 and WX = 5
So, according to (1)
TU = UV = VW = WT = 8
And according to (2)
WX = UX = 5
And ΔWXV is a right triangle at ∠x
So, XV² = WV² - WX² = 8² - 5² = 64 - 25 = 39
∴XV = √39
So, XV = XT = √39
So, the missing measure of a rhombus are as following:
- TU = UV = VW = WT = 8
- WX = UX = 5
- XV = XT = √39
Answer:
After 3 seconds while going up and 6 seconds while coming down
Step-by-step explanation:
Since projectile is launched from ground level with an initial velocity of v 0 feet per second, initial height =0
Height is given by
where v0 = initial velocity = 144
a) When h =288 ft.
At t= 3 or 6 seconds the projectile would be at height 288 ft.
So while going up after 3 seconds it wouldbe at a height of 288 ft and while coming after 6 seconds.
Answer: 10 or 12
Step-by-step explanation:
Answer:
B. A linear, partial variation
Step-by-step explanation:
We know that speed = distance / time. From the table we have a linear function, and it's indirect, or partial.
Answer:
B
Step-by-step explanation:
x% of 6 = 5.25
x 6 = 5.25
= x
x = 87.5 %
discount = 100 - 87.5 %
= 12.5 %
