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emmasim [6.3K]
3 years ago
9

Which of these is an algebraic expression? A. 1 + 2 B. 2b – 5 C. 6 × 4 D. 102

Mathematics
1 answer:
Alexxx [7]3 years ago
3 0
The answer is b because of the letter in the answer.
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Last questions, plz help
Goryan [66]

Answer:

9. a_n=7+6n

10. a_n=a_{n-1}+7

Step-by-step explanation:

9. Given the sequence

13, 19, 25, ...

In this sequence,

a_1=13\\ \\a_2=19\\ \\a_3=25\\ \\...

Note that

a_2-a_1=19-13=6\\ \\a_3-a_2=25-19=6,

then the common difference in this sequence is d=6

You have

a_1=13\\ \\d=6,

then the explicit formula is

a_n=a_1+(n-1)d\\ \\a_n=13+(n-1)\cdot 6\\ \\a_n=13+6n-6\\ \\a_n=7+6n

10. Given the sequence

-10,-3, 4, 11, ...

In this sequence,

a_1=-10\\ \\a_2=-3\\ \\a_3=4\\ \\a_4=11\\ \\...

Note that

a_2-a_1=-10-(-3)=-10+3=-7\\ \\a_3-a_2=-3-4=-7\\ \\a_4-a_3=11-4=7,

then the common difference in this sequence is d=7

You have

a_1=-10\\ \\d=7,

then the recursive formula is

a_n=a_{n-1}+d\\ \\a_n=a_{n-1}+7

5 0
3 years ago
What is 40% of a number is added to the number, the result is 182
hjlf

The answer to your question is 130.

8 0
3 years ago
Diana's parents keep a chart on the wall where they mark how much Diana grows each year. When Diana was 15, she grew 5/6 of an i
otez555 [7]

Answer:

d?

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
At a local University, it is reported that 81% of students own a wireless device. If 5 students are selected at random, what is
Sphinxa [80]

Answer:

34.87% probability that all 5 have a wireless device

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

81% of students own a wireless device.

This means that p = 0.81

If 5 students are selected at random, what is the probability that all 5 have a wireless device?

This is P(X = 5) when n = 5. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.81)^{5}.(0.19)^{0} = 0.3487

34.87% probability that all 5 have a wireless device

5 0
3 years ago
Determine the solution when given the following expression and coordinate.
hodyreva [135]

Here's link to the answer:

tinyurl.com/wpazsebu

6 0
3 years ago
Read 2 more answers
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