Givens
h = 10
b = 4x^y + 2xy^2
Formula
Area = 1/2 b * h
Solution
Substitute the givens into the formula
Area = 1/2 * 10 * (4x^2y + 2xy^2)
Area = 5 * (4x^2y + 2xy^2) What to do next? I would remove the brackets
Area = 5 * 4x^2y + 5 * 2xy^2
Area = 20x^2y + 10xy^2 <<<< Answer
Also possible is to take out more common factors.
The common factor of 4x^2y + 2xy^2 is 2xy and what is left over is 2x + y
So you would have Area = 5*2xy(2x + y)
If you have been given answers please list them.
Answer:
they were on the 21-yard line
Step-by-step explanation:
Answer:
x=5
Step-by-step explanation:
We can use the Triangle Angel Bisector Theorem
AB 2x-1
----------= --------------
AC 3x
9 2x-1
----------= --------------
15 3x
Using cross products
3x*9 = 15*(2x-1)
Distribute
27x = 30x-15
Subtract 30x from each side
27x-30x = 30x-30x-15
-3x = -15
Divide by -3
-3x/-3 =-15/-3
x =5
Answer:
C
Step-by-step explanation:
you need to start by plugging in -2x+4 every were it says y then solve for x when you have found x plug it into one of the equations and solve for y
