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3 years ago

Please do number 4!!!!!

Mathematics

2 answers:

Aleksandr [31]3 years ago

8 0

Answer: 74.5

Step-by-step explanation:

M = money = ?

f = faces she paint = 25 faces

M = 2.50(f) + 12 —> ? = 2.50(25) + 12 = 74.5

Marina86 [1]3 years ago

3 0

Answer:

just put the 25 into the equation, and you get the M, as the money she earn

2.5(25) + 12 = 74.5 that is the amount she earns

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Which situation describes INDEPENDENT events? A) One student is chosen from Classroom A, then a student is chosen from Classroom

WARRIOR [948]

Answer:

Step-by-step explanation:

A) One student is chosen from Classroom A, then a student is chosen from Classroom B

the sets for each probability to happen are different. what happen in first clause is unrelated to the second clause

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3 years ago

If it takes 90 minutes to wait in line to purchase 12 eggs, how many eggs could you purchase if you waited 120 minutes?

AlekseyPX

Answer:

16 eggs

Step-by-step explanation:

we know that

it takes 90 minutes to wait in line to purchase 12 eggs

using proportion

Find out how many eggs could you purchase if you waited 120 minutes

$\frac{90\ min}{12\ eggs}=\frac{120\ min}{x\ eggs}\\\\x=12(120)/90\\\\x= 16\ eggs$

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4 years ago

Prove that:

Lorico [155]

A.)

$\csc^2(x) \tan^2 (x)- 1 = \tan^2(x)$

Use the identities $\csc x = 1 / \sin x$ and $\tan x = \sin x / \cos x$ on the left-hand side

$\begin{aligned}
\text{LHS} &= \csc^2(x) \tan^2 (x)- 1 \\
&= \frac{1}{\sin^2 (x)} \cdot \frac{\sin^2 (x)}{\cos^2 (x)} - 1 \\
&= \frac{1}{\cos^2 (x)} - 1
\end{aligned}$

Make 1 have a common denominator to allow for fraction subtraction
Multiply the numerator and denominator of 1 by cos^2 x

$\begin{aligned} \text{LHS} &= \frac{1}{\cos^2 (x)} - 1 \cdot \tfrac{\cos^2 (x)}{\cos^2 (x)} \\
&= \frac{1}{\cos^2 (x)} - \frac{\cos^2 (x)}{\cos^2 (x)} \\
&= \frac{1 - \cos^2 x}{\cos^2 (x)}
\end{aligned}$

Use Pythagorean identity for the numerator.

If $\sin^2 (x) + \cos^2(x) = 1$ then subtracting both sides by $\cos^2 (x)$ yields $\sin^2(x) = 1 - \cos^2(x)$ . We can substitute that into the numerator

$\begin{aligned} \text{LHS} &= \frac{1 - \cos^2 (x)}{\cos^2 (x)} \\
&= \frac{\sin^2 (x)}{\cos^2 (x)} \\
&= \tan^2 (x) && \text{Since } \tan x = \tfrac{\sin x }{\cos x} \\
&= \text{RHS}
\end{aligned}$

======

b.)

$\dfrac{\sec(x)}{\cos(x)} - \dfrac{\tan(x)}{\cot(x)} = 1$

For the left-hand side:
By definition, $\sec(x) = 1/\cos(x)$ and $\tan (x) = 1/\cot (x)$

$\begin{aligned}
\text{LHS} &= \dfrac{\sec(x)}{\cos(x)} - \dfrac{\tan(x)}{\cot(x)} \\
&= \dfrac{ \frac{1}{\cos(x)} }{\cos(x)} - \dfrac{\frac{1}{\cot(x)}}{\cot(x)} \\
&= \frac{1}{\cos^2 (x)} - \frac{1}{\cot^2(x)} 
\end{aligned}$

Since $\cot (x) = \cos (x) / \sin (x)$

$\begin{aligned} \text{LHS} &= \frac{1}{\cos^2 (x)} - \frac{1}{\frac{\cos^2(x)}{\sin^2(x)} } \\ &= \frac{1}{\cos^2 (x)} -\frac{\sin^2(x)}{\cos^2(x)} \\ &= \frac{1 - \sin^2(x)}{\cos^2 (x)} \end{aligned}$

Using Pythagorean identity, $\cos^2(x) = 1 - \sin^2(x)$ so

$\begin{aligned} \text{LHS} &= \frac{\cos^2(x)}{\cos^2 (x)} \\
&= 1 \\
&= \text{RHS}
\end{aligned}$

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3 years ago

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Dmitrij [34]

Answer:

Step-by-step explanation:

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3 years ago

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Vladimir79 [104]

Answer:

1.) .423

2.).602

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Basically just change your calculator to degree by pressing the mode button then scroll to degree and pressing it. Then type the questions in with the cos tan and. Sin buttons and that’s the answer.

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3 years ago