Answer:
150 feet2 50 feet I hope this helps!
Step-by-step explanation:
24=3r/4
Multiply both sides by 4
24=(3r)/4
(24)*(4)=(3r/4)*(4)
96=3r
Flip the equation
3r=96
Divide both sides by 3
3r/3=96/3
r=32
Now lets check if the answer is good
24=3(32)/4
24= 96/4
24=24
You see , the answer is good .
I hope that's help ! Let me know .
The value of a car after 10 years be $20898.27 if the car rental company assumes each car in their fleet depreciates by 6% per year option (a) $20898.27 is correct.
<h3>What is an exponential function?</h3>
It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent 
where a is a constant and a>1
We can solve this problem by exponential function:
The word depreciate means the price is decreasing.
We can find the value be when the car is 10 years old:
p = 38800(1 - 0.06)¹⁰
p = 38800(0.94)¹⁰
p = 20898.266 ≈ $20898.27
Thus, the value of a car after 10 years be $20898.27 if the car rental company assumes each car in their fleet depreciates by 6% per year option (a) $20898.27 is correct.
Learn more about the exponential function here:
brainly.com/question/11487261
#SPJ1
Answer:
First we need to calculate the are of each wall, since we alredy knew the length (l) and the width (w) which is the height of the wall in this case:
A = wl = 9 . 12 = 108 (ft²)
We also know that he painted 3 walls, we need to multiply our first result by 3, in other words, the area of wall that Brett painted is the sum of the area of three walls: 108 . 3 = 324 (ft²)
Answer:

Step-by-step explanation:
The perimeter of a polygon is equal to the sum of all the sides of the polygon. Quadrilateral PTOS consists of sides TP, SP, TO, and SO.
Since TO and SO are both radii of the circle, they must be equal. Thus, since TO is given as 10 cm, SO will also be 10 cm.
To find TP and SP, we can use the Pythagorean Theorem. Since they are tangents, they intersect the circle at a
, creating right triangles
and
.
The Pythagorean Theorem states that the following is true for any right triangle:
, where
is the hypotenuse, or the longest side, of the triangle
Thus, we have:

Since both TP and SP are tangents of the circle and extend to the same point P, they will be equal.
What we know:
Thus, the perimeter of the quadrilateral PTOS is equal to 