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mestny [16]
3 years ago
5

The figure the Floor Plan of a balcony ,it consists of △ABC and semi-circle ,

Mathematics
1 answer:
ivanzaharov [21]3 years ago
8 0

Step-by-step explanation:

(a) In right triangle ABC,

AC^2 =AB^2 +BC^2  \\  =  {12}^{2} +  {5}^{2}   \\  = 144 + 25 \\  = 169 \\  AC =  \sqrt{169}  \\  \therefore \: AC =  13\: m \\  \\ AC \: is \: the \: diameter \: of \: semicircle \\  \therefore \: r =  \frac{1}{2} \times  AC = \frac{1}{2} \times 13 = 6.5 \: m \\  Circumference \:of \:semi-circle \\ C = \pi \: r = 3.14 \times 6.5 = 20.41 \:m\:

Perimeter of Balcony = 12 + 5 + 20.41 = 37.41 m

(b) Area of balcony

=\frac{1}{2}\times 12\times 5+\frac{1}{2} \pi r^2 \\\\=\times 6\times 5+\frac{1}{2} \times 3.14\times (6.5)^2 \\\\=30+\frac{1}{2} \times 3.14\times42.25\\\\= 30+\frac{1}{2} \times 132.665\\\\= 30 + 66.3325\\\\= 96.3325 \:m^2 \\\\\approx 96. 33\:m^2

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