Answer:
1/ sqrt(1+ln^2(x)) * 1/(ln^2x +1) * 1/x
Step-by-step explanation:
f(x) = sin (tan^-1 (ln(x)))
u substitution
d/du (sin u) * du /dx
cos (u) * du/dx
Let u =(tan^-1 (ln(x))) du/dx =d/dx (tan^-1 (ln(x)))
v substitution
Let v = ln x dv/dx = 1/x
d/dv (tan ^-1 v) dv/dx
1/( v^2+1) * dv/dx
=1/(ln^2x +1) * 1/x
Substituting this back in for du/dx
cos (tan^-1 (ln(x)) * 1/(ln^2x +1) * 1/x
We know that cos (tan^-1 (a)) = 1/ sqrt(1+a^2)
cos (tan^-1 (ln(x)) * 1/(ln^2x +1) * 1/x
1/ sqrt(1+ln^2(x)) * 1/(ln^2x +1) * 1/x
Kenetic friction but i know its kenetic cause of movement
Answer:
540 pages
Step-by-step explanation:
100 pages = 50 mins
??? pages = 270 mins (converted 4hrs 30 mins to minutes)
Now you could cross multiply to find what the number of pages are:
100 pages x 270 mins = 50 mins x ??? pages
27000 = 50 mins x ??? pages
27000/50 = ??? pages
540 = ??? pages
So there are 540 pages in his favourite book.
Substitute 4 for x.
-|4-7|+3
-3+3
f(4) = 0