Express 8x + 4y = 48 in the slope-intercept form. y = _x +

Look at the image to answer.

Vsevolod [243]

No solution is the answer

4 0

3 years ago

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What 7.3087 rounded to the nearest thouaanth

coldgirl [10]

7.309
The thousandth is third number to the right of the decimal. We round 5+ up and 4- we round down.
So we round the decimal into third place, the fourth place is the 7 so we round that up, and we get 7.309

8 0

4 years ago

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Bella pays 8 payments of $5 each to a game store. she returns one game and receivs $20 back. what is the change to the amount of

s2008m [1.1K]

She now has 20 less dollars

5 0

4 years ago

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QS bisects <PQR. If m<PQS = 5x and m<RQS = 2x + 6, then what is m<PQR?

Varvara68 [4.7K]

Answer:

20 degrees

Step-by-step explanation:

If QS bisects Angle PQR, it would mean that Angle PQS and Angle RQS are equal

2x+6=5x

Subtract 2x on both sides

6=3x

Divide by 3 on both sides

x=2

Plug the value of x into either one of the angle measures equation

5x

5(2)=10

If they are equal to one another it would mean that the other angle would be the same measure and you would multiply it by 2

10(2)=20

Therefore 20 degrees is the answer for the measure of Angle PQR

Hope it helped :))

5 0

3 years ago

Which is the distance between parallel lines with the equations 3x-5y=1 and 3x-5y=-3

jonny [76]

Answer:

The distance between parallel lines is $0.6860\ units$

Step-by-step explanation:

we have

$3x-5y=1$ -----> equation A

$3x-5y=-3$ -----> equation B

Line A and Line B are parallel lines, because their slopes are equal

Step 1

Find the slope of the given lines

isolate the variable y in the equation A

$5y=3x-1$

$y=(3/5)x-1/5$

The slope is $m=(3/5)$

Step 2

Find the slope of the perpendicular line to the given lines

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

so

$m1*m2=-1$

we have

$m1=3/5$ -----> given lines

substitute

$(3/5)*m2=-1$

$m2=-5/3$

Step 3

Find the equation of the perpendicular line that pass though the origin

with the slope $m2=-5/3$ and the point (0,0) Find the equation of the line

$y-y1=m(x-x1)$

$y-0=(-5/3)(x-0)$

$y=-(5/3)x$

Step 4

Using a graphing tool

Graph the two parallel lines and the perpendicular line

The intersection points are

$A(-0.2647,0.4412)$ and $B(0.0882,-0.1471)$

see the attached figure

we know that

the distance between the points A and B is the distance between parallel lines

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

substitute the values

$d=\sqrt{(-0.1471-0.4412)^{2}+(0.0882+0.2647)^{2}}$

$d=\sqrt{(-0.5883)^{2}+(0.3529)^{2}}$

$d=0.6860\ units$

8 0

3 years ago

Express 8x + 4y = 48 in the slope-intercept form. y = _x + _