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3 years ago

How to solve this problem?

Mathematics

1 answer:

makkiz [27]3 years ago

3 0

The answer is c because, if u change 15% to a decimal (0.15) then u get 5,250 and when u add that to 35,000 you get 40,250

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Help help i need to get good grades answer correctly please

deff fn [24]

Answer:

the tringale has 3 lines of symmetry

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3 years ago

Sherese draws a segment and labels the endpoints R and S. She uses a compass and straightedge to construct a segment congruent t

Lisa [10]

Answer:

1. Adjust the compass opening to the width of RS

2. Draw point P anywhere

3. Place the compass point on point P and draw an arc.

4. Label any point on the arc as point Q

5. Use a straightedge to connect points P and Q

Step-by-step explanation:

I did the test. This was the right answer.

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3 years ago

Read 2 more answers

Solve the compound inequality 3x + 4 ≤ 7

Ierofanga [76]

Answer:

x ≤ 1

Step-by-step explanation:

3x+4≤ 7

3x + 4 - 4 ≤ 7 - 4

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3 years ago

Bad weather stopped a cricket game for 35 minutes of a schedule 3 1/5 hour match. What percentage of the schedule time was lost?

baherus [9]

Answer:

35 mins lost

out of 3 and 1/2 hrs = 3.5 x 60 mins = 210 mins

%time lost = time lost/total time x 100

= 35/210 x 100

= 1/6 x 100

= 16.66666 %

6 0

3 years ago

Multiplication in GF(24 ): Compute A(x)B(x) mod P(x) in GF(24 ) using the irreducible polynomial P(x) = x 4 + x + 1, where A(x)

tankabanditka [31]

Answer:

Step-by-step explanation:

hello,

i advice you check the question again if it is GF( $2^{4}$ ) or GF(24). i believe the question should rather be in this form;

multiplication in GF( $2^{4}$ ): Compute A(x)B(x) mod P(x) = $x^{4}$ + $x$ +1, where A(x)= $x^{2}$ +1, and B(x)= $x^{3} + x+1$ .

i will solve the above question and i believe with this you will be able to solve any related problem.

A(x)B(x)= $(x^{2} +1) (x^{3}+x+1) mod (x^{4}+x+1 ) = (x^{5} +x^{3}+x^{2} ) + (x^{3}+x+1 ) mod (x^{4} + x+1 )$

= $x^{5}+2x^{3} +x^{2} + x + 1 mod(x^{4}+x+1 )$

= $2x^{2} +1$

please note that the division by the modulus above we used

$\frac{x^{5}+2x^{3}+x^{2} +1 }{x^{4}+x+1}= x+\frac{2x^{3} +1}{x^{4}+x+1}$

5 0

3 years ago