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Leto [7]
2 years ago
9

Just help me on 6 and 7 please

Mathematics
2 answers:
JulsSmile [24]2 years ago
6 0

6)  \frac{9}{4} ÷ \frac{5}{8} \\ = \frac{9}{4} . \frac{8}{5}  = \frac{9.4.2}{4.5} =\frac{18}{5}

7)  2\frac{1}{2} ÷ 4\frac{1}{2} = \frac{5}{2} ÷ \frac{9}{2} = \frac{5}{2} .\frac{2}{9}=\frac{5.2}{2.9} =\frac{5}{9}

ok done. Thank to me :>

TEA [102]2 years ago
4 0
6) 9/4 divided by 5/8
9/4x5/8
9x8/4x5
72/4/5
72/20
18/5
Answer: 18/5

7) 2 1/2 divided by 4 1/2
2x2+1/2 divided by 4 1/2
4+1/2 divided by 4 1/2
5/2 divided by 4 1/2
5/2 divided by 8+1/2
5/2 divided by 9/2
5/2x9/2
5/2x2/9
5x1/9
5/9
Answer: 5/9
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Look at this triangle.<br> B<br> 8 cm<br> A<br> 22 cm<br> Work out length AB.
brilliants [131]

Answer:

23.41cm

Step-by-step explanation:

Using Pythagoras theorem

a²+b² = c²

Where a and b are sides of the triangle and c is the Hypotenuse.

If we substitute the values

B= 8 cm

A= 22 cm

22²+8² = c²

484 + 64= c²

√548 = c

C= 23.41

Hence, length AB is 23.41cm

CHECK THE ATTACHMENT

7 0
2 years ago
Solve the inequality :<br> x-7 ≤ 3x + 1
Nina [5.8K]

Answer:

See below.

Step-by-step explanation:

x-7≤3x+1

 +7     +7

x≤3x+8

-3x -3x

-2x≤8

/-2   /-2

x≥-4

The inequality symbol reverses when divided/multiplied by a negative term.

-hope it helps

6 0
2 years ago
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Simplify the expression.<br> 2+3(x-4) *
Grace [21]

The answer fam is....... 3x - 10

8 0
3 years ago
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Find the derivative of sinx/1+cosx, using quotient rule​
Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}

Now we can simplify that:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}

And we know that:

cos^2(x) + sin^2(x) = 1

then:

f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}

4 0
3 years ago
What is y - 2 = -3 [x-7] written in standard form
Akimi4 [234]
Y=-3x+23

distribute -3, get y alone (add 2 to both sides)
3 0
3 years ago
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