Look at the image for the question.

Which recursive formula can be used to generate the sequence below, where f(1) = 3 and n ≥ 1? 3, –6, 12, –24, 48, … f (n + 1) =

tatuchka [14]

Which recursive formula can be used to generate the sequence below, where f(1) = 3 and n ≥ 1?

3, –6, 12, –24, 48

The recursive formula for this sequence is

f (n + 1) = –2 f(n)

at n=1 f(n)= 3

at n = 2

f(2) = -2 (3) = -6

n = 3

f(3) = -2 (-6) = 12 and so on

8 0

3 years ago

Read 2 more answers

Hellllllllllllllllllllllllllllllllllllllllllllppppppppppppppp

dolphi86 [110]

A circle, of radius r = radius of the sphere

you can think of it in terms of projection the plan projection of the sphere is a circle.

4 0

4 years ago

HELP ME PLEASE!!!!

navik [9.2K]

$24=4\cdot6\\96=16\cdot6\\\\2\sqrt6-4\sqrt{24}+\sqrt{96}=2\sqrt6-4\sqrt{4\cdot6}+\sqrt{16\cdot6}\\\\=2\sqrt6-4\cdot\sqrt4\cdot\sqrt6+\sqrt{16}\cdot\sqrt6=2\sqrt6-4\cdot2\cdot\sqrt6+4\cdot\sqrt6\\\\=2\sqrt6-8\sqrt6+4\sqrt6=(2-8+4)\sqrt6=-2\sqrt6\\\\\text{Answer:}\ -2\sqrt6\\\\\text{Used:}\ \sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}$

5 0

4 years ago

Can someone help me on this pls? It’s urgent, so ASAP (it’s geometry)

Naddik [55]

Given the parameters in the diagrams, we have;

4. ∆ABC ≈ ∆DEF by ASA

5. UW ≈ XZ by CPCTC

6. QR ≈ TR by CPCTC

<h3>How can the relationship between the triangles be proven?</h3>

4. The given parameters are;

<B = <E = 90°

AB = DE Definition of congruency

<A = <D Definition of congruency

Therefore;

∆ABC ≈ ∆DEF by Angle-Side-Angle, ASA, congruency postulate

5. Given;

XY is perpendicular to WZ

UV is perpendicular to WZ

VW = YZ

<Z = <W

Therefore;

∆UVW ≈ ∆XYZ by Angle-Side-Angle, ASA, congruency postulate

Which gives;

UW is congruent to XZ, UW ≈ XZ, by Corresponding Parts of Congruent Triangles are Congruent, CPCTC

6. Given;

PQ is perpendicular to QT

ST is perpendicular to QT

PQ ≈ ST

From the diagram, we have;

<SRR ≈ <PRQ by vertical angles theorem;

Therefore;

∆QRP ≈ ∆TRS by Side-Angle-Angle, SAA, congruency postulate

Which gives;

QR ≈ TR by Corresponding Parts of Congruent Triangles are Congruent, CPCTC

Learn more about congruency postulates here:

brainly.com/question/26080113

#SPJ1

5 0

2 years ago

The repair cost of a Subaru engine is normally distributed with a mean of $5,850 and a standard deviation of $1,125. Random samp

Yuri [45]

Answer:

C. $5180

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Z-scores lower than -2 or higher than 2 are considered unusual.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random normally distributed variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$