Look at the image for the question.

Find the amplitude, period, and phase shift of the function.

Softa [21]

Cosine is transformed in the form:

$f(x)=a\cos(b(x-c))+d$

The amplitude is a

The period of cosine is:

$\frac{2\pi}{b}$

And the phase shift is always by c, so that means our transformed functon in the form mentioned above looks like:

$f(x)=3\cos{(3(x-\frac{\pi}{6}}))+1$

So our period is $\frac{2\pi}{3}$

Our phase shift is by $\frac{\pi}{6}$ units to the right

and our amplitude is 3.

4 0

3 years ago

Jenna had two part-time jobs. She earns $9.50 per hour babysitting for her neighbor and $12.25 per hour working at the Farmers M

Nadusha1986 [10]

Answer:

$91.75

Step-by-step explanation:

babysitting = B

Farmers Market = F

9.5B + 12.25F = Total money earned

9.5 (4.5) + 12.25 (4) = $91.75

3 0

3 years ago

Which of the following numbers is a composite number? A. 11 B. 17 C. 23 D. 27

dimulka [17.4K]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ A composite number is 27. 27 is composite because there are more numbers than 1 and itself that can be multiplied to create 27. The two other numbers to make 27 are 3 x 9. All the other answer choices are prime numbers because no other numbers besides 1 and itself can be multiplied to make that number.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

5 0

3 years ago

Read 2 more answers

The accounting department analyzes the variance of the weekly unit costs reported by two production departments. A sample of 16

dusya [7]

Answer:

$F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2$

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have $n_2 -1 =16-1=15$ and for the denominator we have $n_1 -1 =16-1=15$ and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

$p_v =2*P(F_{15,15}>2.2)=0.138$

For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different

Step-by-step explanation:

Information given

$n_1 = 16$ represent the sampe size 1

$n_2 =16$ represent the sample 2

$s^2_1 = 2.5$ represent the sample deviation for 1

$s^2_2 = 5.5$ represent the sample variance for 2

$\alpha=0.10$ represent the significance level provided

The statistic is given by:

$F=\frac{s^2_2}{s^2_1}$

Hypothesis to test

We want to test if the variations in terms of the variance are equal, so the system of hypothesis are:

H0: $\sigma^2_1 = \sigma^2_2$

H1: $\sigma^2_1 \neq \sigma^2_2$

The statistic is given by:

$F=\frac{s^2_2}{s^2_1}=\frac{5.5}{2.5}=2.2$

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have $n_2 -1 =16-1=15$ and for the denominator we have $n_1 -1 =16-1=15$ and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

$p_v =2*P(F_{15,15}>2.2)=0.138$

For this case the p value is highert than the significance level so we haev enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviations are not significantly different

5 0

3 years ago

Simplify 4 to the 7th over 5 squared all raised to the 3rd power

alisha [4.7K]

<h2>Answer:</h2>

$\left(\frac{4^{21}}{5^6}\right)$