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borishaifa [10]

2 years ago

10

Read the sentence below and answer the following question: Roy was very careful to cleave the apple into even portions. What doe

s the word cleave mean in the context of this sentence? O Hack: to sever with blows O Chop: to deliver a cutting strike O Divide: to separate into parts O Part: to separate

1 answer:

irga5000 [103]2 years ago

5 0

To separate into parts

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Match the following equation to the correct situation.

makkiz [27]

Answer:

The correct answer is option B and D.

Step-by-step explanation:

A. Shawn owed 40% of his tuition bill, b, after paying $6.00

= 40%of (b-6)

B. The amount donated to the school was 40% more that $6.00.

Amount donated to the school = b

b=6+40% of b

C. The cost for a coat was 40% of the sum of b and $6.00.

= 40%(b+6)

D. Summer paid $6.00 more than 40% of b.

Amount by summer = x

= 40%b+6

4 0

3 years ago

Cary and his brother took a road trip together. The total number of miles they drove was more than 200. Cary drove for 50 miles.

Brilliant_brown [7]

Answer:

Step-by-step explanation:

The trick is not to include anything under and including 150 miles. So A B and C are not to be checked.

D and E are both true.

5 0

3 years ago

Read 2 more answers

What is 4627926 rounded to the nearest 100000

Hunter-Best [27]

500000 that's the answer

6 0

3 years ago

Read 2 more answers

Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1

alexandr1967 [171]

Answer:

$a) \simeq 0.3012$ $b) \simeq 0.0494$ c) $\simeq 0.2438$

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, $\frac{1.2}{4}$

= 0.3 collisions per month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

P(X =x) = $\frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}
$

for x ∈ N ∪ {0}

= 0 otherwise --------------------------------------(1)

here, $\lambda = 0.3$ collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

P(X = 0) = $\frac{e^{-0.3}\times {\0.3}^{0}}{0!}
$

$\simeq 0.7408182207$ ------------------------------------(2)

Now, since we are calculating this for 4 months,

so, P(No collision in 4 month period)

= $0.7408182207^{4}$

$\simeq 0.3012$ -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

P(X =1) = $\frac{e^{-0.3}\times {\0.3}^{1}}{1!}
$

$\simeq 0.2222454662$ ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

= $0.2222454662^{2}$

$\simeq 0.0494$ -----------------------------------------(5)

1 collision in 6 months period means

$\frac{1}{6}$ collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6] (which is to be estimated)

= $\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}$

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

$\simeq 0.6543894283$ -------------------------------------------(6)

So,

P(1 collision in 6 month period)

= $0.6543894283^{6}$

$\simeq 0.0785267444$ ------------------------------------------------(7)

So,

P(No collision in 6 months period)

= $(P(X =0)^{6}$

$\simeq 0.1652988882$ ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

$\simeq 0.2438$ ---------------------------------------------(9)

7 0

2 years ago

Help me pls i give brainliest

Yakvenalex [24]

Answer:

away from the origin at a decreasing velocity

Step-by-step explanation:

I think this is right.

I hope this helps! (✿◕‿◕✿)

7 0

3 years ago