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borishaifa [10]
2 years ago
10

Read the sentence below and answer the following question: Roy was very careful to cleave the apple into even portions. What doe

s the word cleave mean in the context of this sentence? O Hack: to sever with blows O Chop: to deliver a cutting strike O Divide: to separate into parts O Part: to separate​
Mathematics
1 answer:
irga5000 [103]2 years ago
5 0
To separate into parts
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Match the following equation to the correct situation.
makkiz [27]

Answer:

The correct answer is option B and D.

Step-by-step explanation:

A. Shawn owed 40% of his tuition bill, b, after paying $6.00

= 40%of (b-6)

B. The amount donated to the school was 40% more that $6.00.

Amount donated to the school = b

b=6+40% of b

C. The cost for a coat was 40% of the sum of b and $6.00.

= 40%(b+6)

D. Summer paid $6.00 more than 40% of b.

Amount by summer = x

= 40%b+6

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2 years ago
Cary and his brother took a road trip together. The total number of miles they drove was more than 200. Cary drove for 50 miles.
Brilliant_brown [7]

Answer:

Step-by-step explanation:

The trick is not to include anything under and including 150 miles. So A B and C are not to be checked.

D and E are both true.

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3 years ago
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Hunter-Best [27]

500000 that's the answer
6 0
3 years ago
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Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1
alexandr1967 [171]

Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, \frac{1.2}{4}

= 0.3 collisions per  month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}


                                                           for x ∈ N ∪ {0}

                       =  0 otherwise --------------------------------------(1)

here, \lambda = 0.3 collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}


                      \simeq 0.7408182207 ------------------------------------(2)

Now, since we are calculating  this for 4 months,

so, P(No collision in 4 month period)

     =0.7408182207^{4}

     \simeq 0.3012  -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

           P(X =1) = \frac{e^{-0.3}\times {\0.3}^{1}}{1!}


                      \simeq 0.2222454662 ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

                =0.2222454662^{2}

                \simeq 0.0494 -----------------------------------------(5)

1 collision in 6 months period means

                                \frac{1}{6} collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6]  (which is to be estimated)

=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

\simeq 0.6543894283-------------------------------------------(6)

So,

P(1  collision in 6 month period)

  =  0.6543894283^{6}

   \simeq 0.0785267444 ------------------------------------------------(7)

So,

P(No collision in 6 months period)

  = (P(X =0)^{6}

   \simeq 0.1652988882 ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

\simeq  0.2438 ---------------------------------------------(9)          

7 0
2 years ago
Help me pls i give brainliest
Yakvenalex [24]

Answer:

away from the origin at a decreasing velocity

Step-by-step explanation:

I think this is right.

I hope this helps! (✿◕‿◕✿)

7 0
3 years ago
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