Find three consecutive odd positive integers such that 5 times the sum of all three is 72more than the product of the first and
second integers.
1 answer:
Let the positive odd numbers be x,x+2,x+4.
According to the question,
5(3x+30)=72+x^2+4x
x^2-13x+42=0
(x-6) and (x-7)=0
x=6 or x=7
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