we know that
total cards=10
even numbers=2,4,6,8,10 -----> 5 cards
the probability that getting an even number is
P=5/10
The probability that getting an odd number
n 1 -----> P=1/10
n3 ----> P=1/10
n5 ---> P=1/10
n7 ----> p=1/10
n 9 ---> P=1/10
The expected value is equal to
EV=(1)(1/10)+(3)(1/10)+(5)(1/10)+(7)(1/10)+(9)(1/10)-(4.20)(5/10)
EV=(25/10)-(21/10)
EV=4/10
EV=$0.40
<h2>The expected value is $0.40</h2>
Part B
Jane can expect to win money after playing the game many times
the answer is
<h2>Jane can expect to gain money</h2><h2>She can expect to win $0.40 per draw</h2>
Answer:
C
Step-by-step explanation:
Answered by Gauthmath
Answer:
x(6x-25y) is your answer ☺️☺️☺️
Answer:
Step-by-step explanation:
If y varies directly as x, then we can write the relation
where k is the constant of proportionality.
We substitute y=-319 when x=29.
This implies that:
The variation equation now becomes
It would be 11.21 percent, hope it helps.
