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scoundrel [369]
3 years ago
5

Find three consecutive odd positive integers such that 5 times the sum of all three is 72more than the product of the first and

second integers.
Mathematics
1 answer:
Alenkasestr [34]3 years ago
8 0
Let the positive odd numbers be x,x+2,x+4.
According to the question,
5(3x+30)=72+x^2+4x
x^2-13x+42=0
(x-6) and (x-7)=0
x=6 or x=7
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Answer:

D

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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2 years ago
Find the unknown length in the right triangle 27cm and 13 cm
Phoenix [80]

use pythagoras:

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3 years ago
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melisa1 [442]

Answer:

D. 18.68

Step-by-step explanation:

27\div \frac{5}{3}-6+53\times (\frac{2}{5})^2

Applying PEMDAS as order of operations.

Solving the exponents first [(\frac{2}{5})^2=\frac{4}{25}]

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Multiplying [53\times \frac{4}{25}=8.48]

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Dividing [27\div \frac{5}{3}=16.2]

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3 years ago
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