1) graph a 2) graph b 3) graph c 4) graph d

VMariaS [17]

If you are needing to find the distance between the two points, you must use a simple formula, cleverly named, the distance formula. Since I can't input special characters into the answer box, I'll explain it the best I can.

( The square root of ( (x - x)^2 + (y - y)^2 ) )

First, we need to find the first x subtracted from the second x, as so:
(4,5) and (7,-9)

4 - 7 = -3

Now, we square the -3.

-3^2 =
-3 * -3 = 9

Next, we have to find the first y subtracted from the second y.
(4,5) and (7,-9)

5 - (-9) = 14

Now, we square the 14.

14^2 =
14 * 14 = 196

Let's see how the numbers fit in the formula:

sqrt((x - x)^2 + (y - y)^2)

sqrt((4 - 7)^2 + (7 - (-9))^2)

sqrt((-3)^2 + (14)^2)

sqrt( 9 + 196 )

This is where we currently are in the formula, all we have to do now is square root the total of 9 + 196.

sqrt( 9 + 196 )
sqrt( 205 )

The square root of 205 = 14.31782106...

There are a few answers you can consider:

1) sqrt(205)
2) 14.32 units
or
3) 14.31782106

Depending on the answer you desire, use the one that sounds the most correct to you. Although all three are correct, it may not be the answer you require.

Hope I could help! If my math is incorrect, or I provided answers you were not looking for, please let know! However, if my answer is correct and well explained, please consider marking my answer as Brainliest! :)

Have a good one.
God bless!

4 0

3 years ago

manufacturing company produces digital cameras and claim that their products maybe 3% defective. A video company, when purchasin

alexdok [17]

Answer:

P(X>17) = 0.979

Step-by-step explanation:

Probability that a camera is defective, p = 3% = 3/100 = 0.03

20 cameras were randomly selected.i.e sample size, n = 20

Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) $nCr q^{r} p^{n-r}$

$nCr = \frac{n!}{(n-r)!r!}$

P(X>17) = P(X=18) + P(X=19) + P(X=20)

P(X=18) = $20C18 * 0.97^{18} * 0.03^{20-18}$

P(X=18) = $20C18 * 0.97^{18} * 0.03^{2}$

P(X=18) = 0.0988

P(X=19) = $20C19 * 0.97^{19} * 0.03^{20-19}$

P(X=19) = $20C19 * 0.97^{19} * 0.03^{1}$

P(X=19) = 0.3364

P(X=20) = $20C20 * 0.97^{20} * 0.03^{20-20}$

P(X=20) = $20C20 * 0.97^{20} * 0.03^{0}$

P(X=20) = 0.5438

P(X>17) = 0.0988 + 0.3364 + 0.5438

P(X>17) = 0.979

The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

6 0

3 years ago

A 100-meter-long christmas train needs 30 seconds to cross a 400-meter-long bridge. assuming the train goes at a steady speed, h

san4es73 [151]

Length of train : 100
length of bridge : 400
distance covered by the train to cross the bridge : (100 + 400) = 500
time taken by the train to cross : 30

speed = distance / time
speed = 500/30
speed = 16.67 meters per second <===

8 0

3 years ago

Terry is filling spherical water balloons with a faucet that puts out 100 cm^3 of water per second. At least rate, it takes Terr

stiv31 [10]

Answer:

its 5 cm

Step-by-step explanation:

its what I got off of Khan

7 0

3 years ago

Mrs. Write makes cookies for the school bake sale. She uses the equation y=0.50x to determine the cost, y, for x cookies. Which

Anni [7]

Answer:D

Step-by-step explanation: just trust me on this one i have a 103% in 9th grade math

3 0

3 years ago