Question

1st person to answer gets brainliest!!!

Answer 1

Answer:

(x-4)^2

Step-by-step explanation:

$x^2-8x+16$

First multiply the outer coefficients 1 and 16: 1x16=16.  Now, the name of the game is to try to figure out if 16 has factors that when added or subtracted will give you the middle term -8.  List factors of 16: 1x16, 2x8, 4x4.  By looking at these pairs of numbers we can see that 4 and 4 will give you 8 but specifically -4-4=-8 and so:

$x^2-8x+16=(x-4)(x-4)=(x-4)^2$

Answer 2

Answer:

A.(x+4)^2

Step-by-step explanation:

If you simplify  A, you would get x^2-8x+16

If you simply b you would get x^2+8y-16

If you simplify c, you would get x^2+8x+16