5. What is the probability that in a random sample of 500 adult Americans, less than 51% admit to cheating?

Mathematics

1 answer:

stealth61 [152]2 years ago

5 0

The right answer is b

Step-by-step explanation:

You do you do the calculations you get that answer

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2. Mark has scored 12, 14, 10, 8, and 5 points in the past 5 basketball games. Write and solve the inequality that

marusya05 [52]

Answer:

Mark must score at least 11 points to have an average of 10 points per game.

Step-by-step explanation:

The average of a set of data is its sum, divided by the number of data points in the set. If p is the number of points Mark scores in his next game, and he wants his average at least 10, then the relation is ...

(12 +14 +10 +8 +5 +p)/6 ≥ 10

49 +p ≥ 60 . . . . . . . . . multiply by 6 and simplify

p ≥ 11 . . . . . . . . . . . subtract 49

Mark must score at least 11 points in the next game to average at least 10 points per game.

_____

<em>Additional comment</em>

Sometimes, it is convenient to work with the average directly. Relative to the average Mark wants (10), his scores so far are +2, +4, 0, -2, -5, for a total of -1. In order to bring the average to the value Mark wants, he must bring this total to 0 or higher. That is, he must score at least 10+1 = 11 points in his next game.

5 0

2 years ago

M ACB = 65. m ECA =?

Kaylis [27]

Is there a diagram I can look at?

4 0

2 years ago

Name the adjacent angles in the diagram below:

harkovskaia [24]

Hey there!

In this picture, we have many pairs of adjacent angles:

1 and 2

2 and 4

4 and 3

3 and 1

This is because these pairs are being connected by a vertex and a side.

Hope it helps and have a great day!!!

5 0

2 years ago

Please help will mark Brainly

Brilliant_brown [7]

Answer:

Step-by-step explanation:

This is not a linear relationship, it doesn't have a set increase or uniform slope and it seems more like an exponential or quadratic curve to me when I graph it. As you can see you cant draw a straight line through the data points so it cannot be a linear relationship.