Answer:
1250
Step-by-step explanation
pretty sure that's the answer.
Answer:
Step-by-step explanation:
Given the coordinate points (6, -3) and (7, -10), we are to find the equation of a line passing through this two points;
The standard equation of a line is y = mx+c
m is the slope
c is the intercept
Get the slope;
m = Δy/Δx = y2-y1/x2-x1
m = -10-(-3)/7-6
m = -10+3/1
m = -7
Get the intercept;
Substitute the point (6, -3) and m = -7 into the expression y = mx+c
-3 = -7(6)+c
-3 = -42 + c
c = -3 + 42
c = 39
Get the required equation by substituting m = -7 and c= 39 into the equation y = mx+c
y = -7x + 39
Hence the required equation is y = -7x + 39
Answer:
2
Step-by-step explanation:
The equation is mx+b=y
The equation is not simplified yet.
2y-4x=1
Add 4x to both sides
2y=1+4x
Divide by 2
1/2+2x
For this just identify. M=slope. The number next to the x is 2. So the answer is 2
Only x-intercept because if you want to know about x-intercepts so y will be zero (y=0)
then 0 =4x^2 -12x + 9
0=(2x-3)(2x-3)
0=2x-3
so x=3/2 that is x-intercept
