All categories

2 years ago

Can anyone help me figure out the 2 square 3 is? and show step by step. Thank you

Mathematics

2 answers:

taurus [48]2 years ago

8 0

like 3 squared? or 2 cubed?

BlackZzzverrR [31]2 years ago

8 0

You mean something like 2^3 or 3^2?

If you mean 2^3, it's pretty much multiplying 2 three times. It would look like:

2 x 2 x 2, which would equal 8. You start off with 2 x 2 = 4, then you take the 4 and multiply it by 2 so it will equal 8.

If you mean 3^2, it's the same thing, except you're multiplying 3 two times. It would look like this:

3 x 3, which equals 9.

You might be interested in

Solve the inequality 47.75 + x < 50 to determine how much more weight can be added to Li's suitcase without going

ehidna [41]

Answer:

Answer Choice A

Step-by-step explanation:

I took this assignment

(please give brainliest)

8 0

2 years ago

Read 2 more answers

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

Joaquim is baking giant cookies for the school bake sale. They will be sold for $20 for one large cookie or $20 for three small

velikii [3]

Small i believe
Because sure the large is bigger but you get more with the small cookies

8 0

3 years ago

36x+72xy+27xy factor the expression.

nexus9112 [7]

Answer:

9x(4+8y+3y)

Step-by-step explanation:

36x+72xy+27xy

9x(4+8y+3y)

4 0

3 years ago

Higher Order Thinking Which do you

GenaCL600 [577]

Answer:

I think 4 x 3.2/5 is higher or greater because the values which it is multiplying a very high and the value at which 3 ×4.2/ 5 is very low compared to the first value

Step-by-step explanation:

hope it helps please mark me brainliest answer

4 0

2 years ago